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2 years ago

5

The total square footage of mini storage units being rented in a city is graphed to forecast future demand. The scatter plot has

a trend line y=0.538x + 9.02, where x = 0 is the year 2005 and y is the total area rented (in ten thousand square feet) of all mini storage units in the city. If the total area rented continues to increase at the same rate, about how many square feet of mini storage units will be needed by the year 2018?
A 190,000 sq ft
B 160,000 sq ft
C 19,000 sq ft
D 16,000 sq ft

2 answers:

Monica [59]2 years ago

5 0

Answer:

B 160,000 sq ft

Step-by-step explanation:

2018 is 13 years after 2005.

Put x=13 in the equation and evaluate:

... y = 0.538·13 +9.02 = 6.994 +9.02 = 16.014

This is the number of 10,000 sq ft, so the required area is ...

... 16 times 10,000 sq ft = 160,000 sq ft.

Amanda [17]2 years ago

5 0

Answer:

D) 16,000 sq ft

Step-by-step explanation:

The scatter plot has a trend line y = 0.538x + 9.02, where "x" represents the number years and "y" represents the area rented.

x =0, when the year 2005

Here we need to find the storage area needed in the year 2018

Therefore, x = 13 in the year 2018.

Now plug in x = 13 in the given equation and find the value of y.

y = 0.538(13) + 9.02

y = 6.99 + 9.02

y = 16.01 thousand square feet

y = 16.01 *1000

y = 16,010 square feet

The nearest approximate value 16,000 sq.ft

The answer is D) 16,000 sq ft

Thank you.

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stealth61 [152]

Answer:

1) Decimal $25= (25)_{10}$

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3) Octal $25= (31)_8$

4) Hexadecimal $25= (19)_{16}$

Step-by-step explanation:

Given : Integer is 25

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

Solution :

1) Integer into decimal - To convert into decimal the base goes to 10.

So, $25= (25)_{10}$

2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

2 | 25

2 | 12 R=1 ←

2 | 6 R=0 ↑

2 | 3 R=0 ↑

2 | 1 → R=1 ↑

So, $25= (11001)_2$

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

8 | 25

| 3 → R=1

So, $25= (31)_8$

4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.

Divide 25 by 16 and note down the remainders.

16 | 25

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A knitted hat pattern comes in 4 styles with 4 stitch options and 3 sizes, and there are 7 yarns appropriate for the hat. Disreg

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Using the normal distribution and the central limit theorem, it is found that there is a 0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

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Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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Mean of 700g means that $\mu = 700$
Standard deviation of 21g means that $\sigma = 21$
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The probability of finding a sample mean mass of 695g or below is the p-value of Z when X = 695, thus:

$Z = \frac{X - \mu}{\sigma}$

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$Z = \frac{X - \mu}{s}$

$Z = \frac{695 - 700}{2.625}$

$Z = -1.905$

$Z = -1.905$ has a p-value of 0.0284.

0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

A similar problem is given at brainly.com/question/22934264

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Read 2 more answers

Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

$(x,y)\rightarrow (-x,y)$

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

$(x,y)\rightarrow (x+3,y-5)$

$M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)$

$N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)$

$O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)$

$P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)$

$Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)$

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

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