Answer: C. Significant at 0.036
Step-by-step explanation:
Given:
Number of selected samples Ns= 500
Number of airplane that arrive on time Na = 482.
Number of airplane that arrive late Nl = 500 - 482 = 18
The probability that an airplane arrive late:
P(L) = Nl/Ns
P(L) = 18/500
P(L) = 0.036
Interpret an event as significant if its probability is less than or equal to 0.05.
Since P(L) < 0.05
P(L) = Significant at 0.036
Option C is your answer.
a² + b² = c²
4² + s² = (√32)²
16 + s² = 32
s² = 16
s = 4
The question is asking whether it is true or false so my answer is true.
