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Romashka-Z-Leto [24]
2 years ago
6

Quadrilaterals WXYZ and BADC are congruent. In addition, WX ≅ DC and XY ≅ BC. If AD = 4 cm and AB = 6 cm, what is the perimeter

of WXYZ?
Mathematics
2 answers:
Yanka [14]2 years ago
6 0

If <u>quadrilaterals</u> WXYZ and BADC are <u>congruent</u>, then their corresponding <u>sides</u> are congruent.

Given that

  • WX≅DC,
  • XY≅BC,

you can state that

  • YZ≅AB,
  • WZ≅AD.

If AD = 4 cm and AB = 6 cm, then WZ = 4 cm and YZ = 6 cm. Opposite rectangle sides are congruent, then XY = 4 cm and WX = 6 cm.

The perimeter of WXYZ is

P = WX + XY + YZ + WZ = 6 + 4 + 6 + 4 = 20 cm.

Answer: 20 cm

Effectus [21]2 years ago
5 0

Answer:

<h2>The answer is B on eg</h2><h2>trust me it's right</h2>

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The vertices of rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0). what is the perimeter of the rhombus?
Harman [31]

Answer: 20 unit.

Step-by-step explanation:

Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).

Where, de, ef, fg, gd are sides of the rhombus defg.

By the distance formula,

de = \sqrt{(4-1)^2+(0-4)^2}

=\sqrt{3^2+4^2}

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Thus, the side of rhombus = 5

By the property of rhombus,

de =  ef = fg = gd = 5 unit.

Thus, the perimeter of the given rhombus defg = de +  ef + fg + gd = 5+5+5+5 = 20 unit

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Answer: 2.76 g

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\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

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Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

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