Hope you can see the picture and understand the drawings.
It can seem complex at first but you just have to think it through.
I use pythagoras' theorem to find the diagonal of the base square and then use that information along with the height with the aid of that ever so handy pythagoras' theorem to find the length of the slope.
Answer:
This question contains some errors; the correct question is:
You pack sandwiches for a mountain hike with your friends. Each sandwich takes 2 slices of bread, and each hiker eats one sandwich. How many slices of bread are used for n hikers? Write your answer as an expression.
The answer is:
(2n) slices of bread for n hikers
Step-by-step explanation:
According to the question, sandwiches packed for a mountain hike with friends is made of two (2) slices of bread.
Each hiker gets one sandwich
This, n hikers will get n× 1 sandwich
= (n) sandwiches.
If 1 sandwich contains 2 slices of bread, then (n) sandwiches for n hikers will contain:
(2 × n) slices of bread
That is, (2n) slices of bread.
The expression is (2n).
The angles are supplementary, therefore totaling them at 180°.
And because I'm bored, I'll solve for x for you!
(x + 25) + (9x + 10) = 180
10x + 35 = 180
Subtract 35 from both sides.
10x = 145
Divide by 10 on both sides.
x = 14.5
Answer:
12
Step-by-step explanation:
610 divided by 55 = 11.09
but since u cant have 11.09, u need 12
Answer:
V(t) = 25000 * (0.815)^t
The depreciation from year 3 to year 4 was $2503.71
Step-by-step explanation:
We can model V(t) as an exponencial function:
V(t) = Vo * (1+r)^t
Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.
We have that Vo = 25000, r = -18.5% = -0.185, so:
V(t) = 25000 * (1-0.185)^t
V(t) = 25000 * (0.815)^t
In year 3, we have:
V(3) = 25000 * (0.815)^3 = 13533.58
In year 4, we have:
V(4) = 25000 * (0.815)^4 = 11029.87
The depreciation from year 3 to year 4 was:
V(3) - V(4) = 13533.58 - 11029.87 = $2503.71
