What cycle time would match capacity and demand if demand is 173 units a day, there are 2 shift(s) of 458 minutes each, and work
1 answer:
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Answer:
(a) 0.7967
(b) 0.6826
(c) 0.3707
(d) 0.9525
(e) 0.1587
Step-by-step explanation:
The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and variance <em>σ</em>² = 36.
(a)
Compute the value of P (X > 5) as follows:
Thus, the value of P (X > 5) is 0.7967.
(b)
Compute the value of P (4 < X < 16) as follows:
Thus, the value of P (4 < X < 16) is 0.6826.
(c)
Compute the value of P (X < 8) as follows:
Thus, the value of P (X < 8) is 0.3707.
(d)
Compute the value of P (X < 20) as follows:
Thus, the value of P (X < 20) is 0.9525.
(e)
Compute the value of P (X > 16) as follows:
Thus, the value of P (X > 16) is 0.1587.
**Use a <em>z</em>-table for the probabilities.
I found a graph with the same problem, so I guess this is the graph to be based on. To find the rate, just determine the slope between any two points along the line. Suppose these points are: (30,10) and (50,20).
Slope = (20 - 10)/(50 - 30) = 1/2
<em>The correct answer should be: the rate of change is 1 cm per 2 weeks, or 1/2.</em>
Slope = (20 - 10)/(50 - 30) = 1/2
<em>The correct answer should be: the rate of change is 1 cm per 2 weeks, or 1/2.</em>