1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
Answer:
Commitment Adherence Percentage = 81.
%
Step-by-step explanation:
The time period Amy scheduled herself, t = 8 a.m. - 1 p.m. from Sunday through Wednesday
The period she released her interval = 11 a. m. - 1 p.m.
Commitment Adherence Percentage = Service Minutes/(Posted Minutes + Released Lockdown Minutes) × 100
Posted minutes = 5 hours/day × 60 minutes × 4 days = 1200 minutes
Serviced minute = 5 hours/day × 60 minutes × 3 days + 3 hours × 60 minutes/hour = 1,080 minutes
Released minutes = 2 hours × 60 minutes/hour = 120 minutes
Commitment Adherence Percentage = (1,080/(1,200 + 120)) × 100 = 81.%
Answer:
<u>(h * h)(10) = 16</u>
Step-by-step explanation:
We should know that: (f*g)(x) = f(x)*g(x)
Given: h(x) = 6 - x
∴(h * h)(x) = (6-x) (6-x) = (6-x)²
To find (h * h)(10), substitute with x = 10 at (h * h)(x)
∴ (h * h)(10) = (6-10)² = (-4)² = 16
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Note: if we want to find (hoh)(10)
(hoh)(x) = h[h(x)] = 6 - (6 - x) = 6 - 6 + x = x
∴ (hoh)(10) = 10
