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Montano1993 [528]
2 years ago
7

Work out percentage change to 2 decimal places when a price of £97 is increased to £99.99

Mathematics
1 answer:
Korvikt [17]2 years ago
8 0

Answer:

2.99

Step-by-step explanation:

99.99 - 97 = 2.99

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A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
2 years ago
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The scale for the drawing of a rectangular playing field is 2 inches= 5 feet. Write an equation you can use to find the dimensio
iris [78.8K]

Answer:

Step-by-step explanation:

Given:

Scale

2 inches : 5 feet

Actual dimensions

Let x be the dimension of the scale drawing (in inches) and y, the corresponding dimension of the actual field (in feet).

Scaled dimension = scale × actual dimension

Actual dimension, x = y × 5 ft/2 in

2 × x = 5 × y

Equation:

2x = 5y

3 0
2 years ago
49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively
mrs_skeptik [129]

Answer:

Stratified sampling

Step-by-step explanation:

In the question, students are selected from subgroups of Sophomore, Junior, and Senior classes.

We are told that 49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively.

This means that the sample numbers of 49, 34 and 48 students were selected in proportion to the subgroup sizes of 496, 348, and 481 students respectively.

Thus, due to the fact that subgroups were selected & that sample number of students were also selected in proportion to their respective subgroup sizes, this is therefore a stratified sampling.

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2 years ago
Leslie is running for a political office. She wants to poll adults in her district to understand their stances on various issues
Liula [17]
Believe it’s a right
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2 years ago
Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E
gtnhenbr [62]

The correct question as understood from the statement is:

Determine which equations have the same solution set as 2/3 – x + 1/6 = 6x by recognizing properties, rather than solving. Check all that apply.

a) 4 - 6x + 1 = 36x

b) 5/6 - x = 6x

c) 4 - x + 1 = 6x

d) 5/6 + x = 6x

e) 5 = 30x

f) 5 = 42x

Answer:

Options: a, b and f

Step-by-step explanation:

The given equation is:

\frac{2}{3}-x+\frac{1}{6}=6x

Adding x to both sides, we get:

\frac{2}{3}+\frac{1}{6}=7x\\\\ \frac{4}{6}+\frac{1}{6}=7x\\\\  \frac{5}{6}=7x\\\\  5=42x\\\\ x=\frac{5}{42}

Option a) 4 - 6x + 1 = 36x

Moving 6x to the right hand side of the equation and simplifying the answer, would give us 5 = 42x, which is the same as the second last equation in above simplification. Thus this equation has the same roots.

Option b) 5/6 - x = 6x

Moving x to other side will give us the same equation as we got in 3rd last step of the above simplification. Thus this equation has the same roots.

Option c) 4 - x + 1 = 6x

Moving x to other side, and simplifying the result gives us an equation which does not match with the equations in above simplifications. So, this equation does not have the same root.

Option d) 5/6 + x = 6x

Moving x to other side, and simplifying the result gives us an equation which does not match with the equations in above simplifications. So, this equation does not have the same root.

Option e) 5 = 30x

This does not match with the second last step of the above simplification. So, this equation does not have the same root.

Option f) 5 = 42x

This equation matches with the second last step of the above simplification.  Thus this equation has the same roots.

3 0
2 years ago
Read 2 more answers
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