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1 year ago

7

The Sluggers go out for pizza after a game. Five large pizzas plus three medium pizzas together have 110 slices. Two large pizza

s plus nine medium pizzas have 122 slices. How many slices are in a large pizza?

1 answer:

chubhunter [2.5K]1 year ago

4 0

Hi the call you have a good day bye bye the call

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Sasha is bisecting a segment. First, she places the compass on one endpoint, opens it to a width larger than half of the segment

FrozenT [24]

Answer:

A) Swing arcs on both sides to intersect the first two arcs created.

Step-by-step explanation:

Bisecting a segment is cutting a line into two equal parts with a line bisector.

The steps involved are;

Placing a compass on one endpoint
Opening the compass to a width larger than half of the segment
Swinging an arc on either side of the segment
While maintaining the same width, place the compass on the other endpoint
Swing arcs on both sides of the segment to intersect the first two arcs created
Using a ruler placed at the points of intersection of the arcs, draw the line bisector.

Sasha was now at step four.

7 0

2 years ago

Read 2 more answers

* 6. You plan to rent a car from XYZ Car Rental Company for a flat rate of $35 a day.

Anni [7]

Answer:

$f(x) = \left \{ {{35x + 10, x \leq 3} \atop {35x + 5x = 40x, x>3}} \right.$

Step-by-step explanation:

Let x be the number of days you want to rent

The flat rate for car rental is $35 a day

As for insurance, $10 for 3 days or fewer, and $5 per day if more than 3 days that is

$\left \{ {{10, x \leq 3} \atop {5x, x>3}} \right.$

Combine this with the flat rental rate $35 a day and we have

$f(x) = \left \{ {{35x + 10, x \leq 3} \atop {35x + 5x = 40x, x>3}} \right.$

7 0

2 years ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

5 0

1 year ago

In a certain classroom ,12.5% of the students own at least one pet. If there are 32 students in the classroom,how many students

Y_Kistochka [10]

Answer:

28

Step-by-step explanation:

Given that 12.5% of students own at least 1 pet, then the percentage of students who do not own a pet is

100% - 12.5% = 87.5%

Calculate 87.5% of 32, that is

$\frac{87.5}{100}$ × 32

= 0.875 × 32 = 28 ← number of students who do not own a pet

8 0

2 years ago

Read 2 more answers

(1 Convert the integral below to polar coordinates and evaluate the integral. ∫4/2√0∫16−y2√yxydxdy∫04/2∫y16−y2xydxdy Instruction

Tanzania [10]

Answer:

A = 0

B = π/4

C = 0

D = 4

Volume = 16

Step-by-step explanation:

∫BA∫DC∫AB∫CD is shown in the picture attached

4 0

2 years ago