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vazorg [7]
2 years ago
14

Tania has 56 liters of milk. She uses the milk to make muffins and cakes. Each batch of muffin requires 7 liters of milk and eac

h batch of cakes require 4 liters of milk. Let x be the number of batches of muffins and y be the number of batches of cakes that Tania can make. Which of the following graphs best shows all the possible number of batches of muffins and cakes that Tania can make? Line joining ordered pairs 0, 8 and 6, 3.5. Shade the portion of the graph below this line which lies within the first quadrant Line joining ordered pairs 0, 8 and 6, 3.5. Shade the portion of the graph above this line which lies within the first quadrant Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph above this line which lies within the first quadrant Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
Mathematics
1 answer:
mihalych1998 [28]2 years ago
4 0
Write the inequalities that are given by the :

<span>x: the number of batches of muffins

y: the number of batches of cakes

</span>Each batch of muffin requires 7 liters of milk and each batch of cakes require 4 liters of milk.

=> liters of milk use = 7x  + 4y

<span>Tania has 56 liters of milk.=> 7x + 4y ≤ 56

Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.

The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.

The line 7x + 4y = 56 has these x and y intercepts:

y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)

x-intercept => y = 0 => 7x = 56 => x = 56/7= 8  => point (8,0)

So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.

Also, you know that x and y are restricted to be positive or zero =>

x ≥ 0

y ≥ 0.

So, the solution region is restricted to the first quadrant.

That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>


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A number, x, rounded to 2 decimal places is 15.38<br>Write down the error interval for x.​
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Answer:

The error interval for x is:

[15.375,15.384]

Step-by-step explanation:

In order to determine the error interval for x, We have to get the all the number which could be rounded off to 15.38.

These number can be listed in order such as:

15.375   15.376   15.377   15.378   15.379   15.380   15.381   15.382   15.383   15.384  

Therefore, the error interval for x is:

[15.375,15.384]

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2 years ago
The lines below are parallel if the slope of the green line is -2 what is the slope of the red line
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Answer:

-2

Step-by-step explanation:

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Walter is making a 300-mile trip from Wichita Falls, Texas to Austin, Texas. After the first 120 miles, he continues driving at
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Answer:

about 135 more miles to go

Step-by-step explanation:

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2 years ago
Read 2 more answers
In the right △ABC with m∠C=90°, m∠B=75°, and AB = 12 cm. Find the area of △ABC.
azamat

Given that ABC is a right angle triangle with m∠C=90°,  m∠B=75° and AB=12cm.

Area of triangle =  

                         =  

So we need to find BC,AC now.

To find them let us take sinB and cosB.

SinB =  

BC = 12* cos B = 12* cos 75

So, area =  

            = 72*sin(75)*cos(75)

            = 36*(2sin(75)cos(75))

            = 36*sin(150) =  18

Hence area of triangle is 18

Hope this helps tbh sorry I was a little late btw (:

7 0
2 years ago
A student placement center has requests from five students for interviews regarding employment with a particular consulting firm
bagirrra123 [75]

Answer: a) 1 / 10

b) 3 / 10

c) 1 / 5

d) 3 / 5

Step-by-step explanation:

Total number of requests five students for interviews regarding employment with the consulting firm = 5

Number of students that are maths majors = 3

Probability of selecting a maths student is 3 / 5

Number of students that are statistics majors = 2

Probability of selecting a statistics student is 2 / 5

a) the probability that both selected students are statistics majors

= 2 / 5 × 1 / 4 = 2 / 20 = 1 / 10

b) the probability that both students are math majors

= 3 / 5 × 2 / 4 = 6 / 20 = 3 / 10

c) the probability that at least one of the students selected is a statistics major will be p( one statistics and the other, maths) + p( one maths and the other, statistic) - p( both are mathematics)

= (2 / 5 × 1 / 4 ) + ( 2 / 5 × 3 / 4 ) - (3 / 5 × 2 / 4)

= 2 / 10 + 6 / 20 - 6 / 20

= 1 / 5 + 3 / 10 - 3 / 10

= 1 / 5

d) the probability that the selected students have different majors is p(one is maths and the other is statistics) + p(one is statistics and the other is maths)

(3 / 5 × 2 / 4) + (2 /5 × 3 / 4)

= 6 / 20 + 6 / 20 = 12 / 20

= 3 / 5

3 0
2 years ago
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