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kicyunya [14]
2 years ago
11

Alex is x years old. Addison is y years younger. Find their combined age in 10 years’ time.

Mathematics
1 answer:
stira [4]2 years ago
4 0

Answer:

x+10-y

Step-by-step explanation:

i'm not 100% sure about this response, but i'd assume the answer is like this for the following reasons:

alex is x years old, and 10 years have passed, meaning 10 years are added onto his age (x+10). addison is still the same amount of years apart from him in age, so you subtract y from that (x+10-y).

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A pool is comprised of a rectangle with 2 semicircles on the ends.
pychu [463]

Answer:

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

Length = 100 m

Width = 52 m

Area of rectangle = 100 × 52 = 5200 m²

A semicircle is half of a circle

The formula for determining the area of a semicircle is

Area = 1/2 × πr²

Diameter = 52 m

Radius = diameter/2 = 52/2

Radius = 26 m

The area of each semicircle is

1/2 × 3.14 × 26² = 1061.32 m²

The area of the surface of the pool is

1061.32 + 1061.32 + 5200 = 7322.64 m²

6 0
2 years ago
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For every $10 Glen earns, his parents
irga5000 [103]

10-2 = 8

He can spend $8

$8/$10 = 0.80

0.80 x 100 = 80 %

He can spend 80%

8 0
1 year ago
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
2 years ago
Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi
tiny-mole [99]

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

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2 years ago
Christy spent $500 over her budget on gifts during the holidays. In addition to her regular job, she took a part-time job at the
Deffense [45]
Christy will have to work 50 hours to pay off her debt.

500 divided by 10 = 50.

Hope this helped!
5 0
2 years ago
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