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lubasha [3.4K]
2 years ago
15

What is the value of x in the equation below? –3 – (–8) – (–2) = x

Mathematics
1 answer:
Ghella [55]2 years ago
3 0

Answer:

–3 – (–8) – (–2) = x

Step-by-step explanation:

–3 – (–8) – (–2) = x

Subtracting a negative is adding a positive

-3 +8+2 =x

Starting from left to right

5 +2 =x

7 =x

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A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.
qwelly [4]
A = 0.9 o 
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<span>so, the orange is 11% heavier than the apple. 

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A gas stove that normally sells for $749 is on sale at a 30% discount. What is the sale price of the gas stove
Virty [35]
The answer is 224.7 you got to turn 30% into decimal which is 0.30 
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Danica has laid out floor tiles so they form a rectangle with a perimeter of 18 inches.what is the differnce between the greates
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Technically you would have to divide 18 in half which is 9 so 9 is your possible answer.
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1 year ago
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Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

7 0
1 year ago
Which graph represents the function f(x)=x4+4x3−12x2−32x+64?
sp2606 [1]

f(x)=x^4+4x^3-12x^2-32x+64

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So  as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first  graph

x intercepts of first graph is -4  and 2

Plug in -4 for x in f(x) and check whether we get 0

f(x)=x^4+4x^3-12x^2-32x+64

f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0

Now plug in 2 for x and check

f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0

So -4  and 2  are the x intercepts that satisfies f(x)

Hence first option is the graph of f(x)=x^4+4x^3-12x^2-32x+64





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1 year ago
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