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Ray Of Light [21]
2 years ago
10

A clothing store is having a sale where all shirts are 40% off and all the pairs of pants are 30% off. Which of these are true?

Choose the TWO correct answers. A) jerry wants to buy one pair of pants originally priced at &40$ and a shirt is originally priced at $45. He will pay a total sale price of $55. B) Mary buys two shirts originally priced at $25. She will pay a total sale price of $35. C) Michael buys a pack of four shirts on sale of $37.80. The pack of shirts was originally priced at $54. D) Chantal buys a pair of pants for sale price of $40.60. The pair of pants was originally priced at $58.
Mathematics
1 answer:
const2013 [10]2 years ago
4 0

Answer:

Step-by-step explanation:

A. "a pair of pants originally priced at &40$ and a shirt originally priced at $45. He pays $55"—correct

(1-0.30)$40 + (1-0.40)$45 = $55

B. "Mary buys two shirts originally priced at $25. She will pay $35."—incorrect

2×(1-0.40)$25 = $30

C. "a pack of four shirts on sale for $37.80. The pack of shirts was originally priced at $54"—incorrect

(1-0.40)$54 = $32.40

D. "a pair of pants for sale price of $40.60. The pair of pants was originally priced at $58."—correct

(1-0.30)$58 = $40.60

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The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau
AleksandrR [38]

Answer:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

Step-by-step explanation:

We have the following info given:

\bar X_1 = 240 sample mean for medium Pizzas from Prim's

\bar X_2 = 210 sample mean for medium Pizzas from Pizza Place

s_1 =8.6 sample deviation for Prim's

s_2 =5.7 sample deviation for Pizza Palca

n_1 =n_2 = 100  sample size selected for each case

The confidence interval for the difference of means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

And for the 95% confidence we need a significance level of \alpha=1-0.95=0.05 and \alpha/2 =0.025, the degrees of freedom are given by:

df= n_1 +n_2 -2= 100+100-2 =98

And the critical value would be

t_{\alpha/2}= 1.984

And replacing we got:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

8 0
2 years ago
Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.
Ghella [55]

Answer:  The required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

Step-by-step explanation:  Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written \frac{1}{4} as many articles as Mustafa has and Gia has written \frac{3}{2} as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper.  Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.

And the solution of the above inequality is as follows :

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.

Thus, the required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

4 0
2 years ago
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To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?
Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

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What is 0.666667 as a fraction ?
Olenka [21]
0.666667 as a fraction is 2/3
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2 years ago
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A town has a population of 2000 and grows at 2% every year. To the nearest year, how long will it be until the population will r
MissTica

Answer:

21 years

Step-by-step explanation:

Use the equation 2000(1.02)^{x} = 3000 where x is the number of years passed.

Once you've solved for it, x=20.475319. Although it's closer to 20 years to the nearest year, it's 21 years since you'll wont reach 3000 in year 20.

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