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1 year ago

Goodlife charges its members $30 per month for a gym membership. They currently have 75 clients.

Mathematics

1 answer:

Sauron [17]1 year ago

4 0

They should charge $40 per membership, and they will make a maximum revenue of $2400

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Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average

lutik1710 [3]

Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.

4 0

1 year ago

Read 2 more answers

A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.

blsea [12.9K]

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

$A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}$

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

$A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}$

Simplifying, we get;

$A=\frac{64 \times 10}{4 (\tan \ 18)}$

$A=\frac{640}{4 (0.325)}$

$A=\frac{640}{1.3}$

$A=642.3$

Rounding off to the nearest whole number, we get;

$A=642 \ cm^2$

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

5 0

1 year ago

The table shows the amount of money LaTasha charges customers to mow their lawns. The table represents a linear function.

sashaice [31]

It is b Latasha charges 10 dollars before she begins to work

5 0

2 years ago

Read 2 more answers

On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid

Anon25 [30]

Answer:

y=7600(5^(t/22))

Step-by-step explanation:

This is going to be an exponential function as it grows rapidly.

This type of question can be solved using the formula y=a(r^x), where a is the inital amount, r the factor by which the amount increases and x is the unit of time after which the amount increases.

x=t/22

a=7600

r=5

∴y=7600(5^(t/22))

5 0

2 years ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

2 years ago