Answer:
The total cost of 5 pillows and 7 sheets is $205.345
Step-by-step explanation:
Let x be the price of pillow case
We are given that the price of the pillows is 3 times as much as the price of a pillow case
Price of pillow = 3x
Price of 2 pillows = 2(3x)=6x
Price of 3 pillow case = 3x
At a store, 2 pillows and 3 pillow cases together cost $73.08.
So, 6x+3x=73.08
9x=73.08

x=8.12
So, Price of 1 pillow case = 8.12
Price of 1 pillow = 3x=3(8.12)=24.36
Price of 3 pillow =3(24.36)=73.08
Let y be the cost of 1 sheet
The total cost of 3 pillows and 4 sheets is $120.82
So, 73.08+4y=120.82

y=11.935
Price of 1 sheet = 11.935
Price of 7 sheets = 7(11.935)=83.545
Price of 5 pillows =5(24.36)=121.8
So,the total cost of 5 pillows and 7 sheets=83.545+121.8=205.345
Hence the total cost of 5 pillows and 7 sheets is $205.345
Answer:
4 nickels
12 dimes
Step-by-step explanation:
Dimes are worth .1 each while nickels are .05 each.
We have 8 more dimes than nickels. Let d represent number of dimes and n for number of nickels. This means we have d=8+n.
If all our nickels and dimes together are worth 1.4 then we have another equation .1d+.05n=1.4
Lets put our equations together:
d=8+n
.1d+.05n=1.4
‐-----------------Plug first equation into second.
.1(8+n)+.05n=1.4
Distribute
.8+.1n+.05n=1.4
Combine like terms
.8+.15n=1.4
Subtract .8 on both sides
.15n=.6
Divide both sides by .15
n=.6/.15=4
Remember there are 8 more dimes so d=8+4=12.
Answer:
D. Windshield replacement
Step-by-step explanation:
A Recurring Cost is a regularly occurring cost or estimated cost which is documented with one record—a Recurring Cost record—that describes the income or expense and its pattern (how often it occurs, the rate at which it increases or decreases, the time period during which the cost applies, and so forth)
Answer: Total amount the stadium would clear for all of these events combined is $1750000
Step-by-step explanation:
Since we have given that
Number of major recording acts are able to play at the stadium = 10
Average profit margin for a concert = $175000
We need to find the amount that the stadium clear for all of these events combined
As we know the formula for "Average"

Hence, total amount the stadium would clear for all of these events combined is $1750000.
Answer:
q = 108-n
Step-by-step explanation:
Given: 108 coins containing only quarters and nickels
q = 108-n
since total number of coins is 108, and n= number of nickels
If you want to know how many of each kind of coin, read on:
First solve the number of quarters and nickels.
If all 108 coins are quarters, the value is 108*0.25 = $27
Since this value exceed the actual by 27-21 = $6,
we replace a number of quarters by nickels.
Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.
So it will take 6/0.2 = 30 replacements.
Therefore there are 108-35 = 78 quarters and 30 nickels.