A cube has side length a. The side lengths are decreased to 50% of their original size. Write an expression in simplest form for
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Answer:
How many units need to be sold to produce the maximum revenue? 1000 units
How many in dollars is the maximum revenue when the maximum of units are sold? $350,000
Step-by-step explanation:
We get max value of a function if we differentiate it and set it equal to 0.
We need to differentiate r(x) and set it equal to 0 and solve for x.
<u><em>That would be number of units sold to get max revenue.</em></u>
<u><em /></u>
<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>
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Before differentiating, we see the rules shown below:
Where
f'(x) is the differentiated function
Now, let's do the process:
So, 1000 units need to be sold for max revenue
Now, substituting, we get:
The max revenue amount is $350,000
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.