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2 years ago

Write the equation for taking away 5 from x gives 10

Mathematics

1 answer:

geniusboy [140]2 years ago

5 0

Answer:

$\boxed{\sf x - 5 = 10}$

Step-by-step explanation:

Taking away 5 from x ⇒ subtracting 5 from x

$\large {\sf x - 5$

Gives 10 ⇒ result is 10

$\large {\sf x - 5 = 10$

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Two numbers are randomly selected on a number line numbered from 1 to 9. Match each scenario to its probability.

Talja [164]

Answer:

1/9; 4/9; 1/12; 1/6

Step-by-step explanation:

the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9

the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9

the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12

the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6

5 0

2 years ago

Read 2 more answers

Using the power series methods solve the 1st order Lane-Emden Equation:

nikklg [1K]

Answer:

Step-by-step explanation:

xy = 2y + xy = 0

Hence, 2y + xy = 0 ---------(1)

Differentiating equation (1) n times by Leibnitz theorem, gives:

2y(n) + xy(n) + ny(n - 1) = 0

Let x = 0: 2y(n) + ny(n - 1) = 0

2y(n) = -ny(n - 1)

∴ y(n) = -ny(n - 1)/2 for n ≥ 1

For n = 1: y = 0

For n = 2: y(1) = -y

For n = 3: -3y(2)/2

For n = 4: -2y(3)

5 0

2 years ago

Titus is asked to prove hexagon FEDCBA is congruent to hexagon

Goshia [24]

Answer:

(x, y) -------> ( - x , y - 10 )

Step-by-step explanation:

Titus is not correct.

There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'

First transformation is Reflection over y-axis , then translation 10 units down.

The final formula is ( - x , y - 10 )

5 0

1 year ago

A new car is purchased for 20700 dollars. The value of the car depreciates are 11% per year. What will the value of the car be,

ASHA 777 [7]

Answer: $5,744.61

Step-by-step explanation:

year 1 = -2,277

year 2 = -2026.53

year 3 = -1803.61

year 4 = -1605.21

year 5 = -1428.64

year 6 = -1271.49

year 7 = -1131.62

year 8 = -1007.17

year 9 = -896.36

year 10 = -797.76

year 11 = -710

you are subtracting 11% from each year.

5 0

2 years ago

A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st

Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample credit hours per quarter = 15.2 credit hours

s = sample standard deviation = 2.3 credit hours

n = sample of students = 250

$\mu$ = population mean credit hours per quarter

Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < $t_2_4_9$ < 1.96) = 0.95 {As the critical value of t at 249 degree of

freedom are -1.96 & 1.96 with P = 2.5%}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $15.2-1.96 \times {\frac{2.3}{\sqrt{250} } }$ , $15.2+1.96 \times {\frac{2.3}{\sqrt{250} } }$ ]

= [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.

8 0

1 year ago

Write the equation for taking away 5 from x gives 10​

Write the equation for taking away 5 from x gives 10