(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Answer: Real world problem is "A student have c toffee he distribute
th part of those toffees to his friends. He gave total 21 toffees to his friend".
Explanation:
Let a student have c number of toffees in his bag.
It is given that he distribute
th part of those toffees to his friends.
The
th part of c toffees is,

The total number of distributed toffees is 21.

It is the same as given equation.
If we change the equation in words it means the
th part of a number c is 21.
It's actually legit 50 pounds because you sound up if it's 5 or more but if it's less it stays the same
Answer: 75
Step-by-step explanation: -14 + 98 =