Titus is asked to prove hexagon FEDCBA is congruent to hexagon
1 answer:
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Answer:
1.75 cm
Step-by-step explanation:
We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.
Now, to increase the profit, the dimensions of the box by 'x' cm.
Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.
Further, it is given that the volume of the new box is 2,208
As, Volume of the box = Length × Breadth × Height
i.e. 2208 = (25-x) × (14-x) × (10-x)
i.e.
i.e.
i.e.
On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.
Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.
Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.
Hence, the dimensions were decreased by 1.75 cm.
Answer: B) 0
Step-by-step explanation:
1. When you add complex numbers you must add the whole parts and then the imaginary parts.
2. One of the properties of complex numbers is called "Additive identity" which is represented by:
3. Then, for the complex number , you have:
4. Therefore, the answer is the option B.