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Olin [163]
2 years ago
8

The table below shows a baseball player’s batting average batting left and right versus left- and right-handed pitches Left-hand

ed pitchers Right-handed pitchers Bats left 0.285 0.175 Bats right 0.215 0.250 Assume these numbers are the probabilities that he will get a hit during an “at bat.” On average, when he bats left 100 times, how many more hits will he get when he faces left-handed pitchers as opposed to right-handed pitchers? 1 2 11 22
Mathematics
1 answer:
Assoli18 [71]2 years ago
5 0

Answer:

C. 11 is the correct answer

Step-by-step explanation:

The table representing the probabilities of player's batting average is,

                        Left-Handed pitchers         Right-Handed pitchers

Bats Left                    0.285                                      0.175

Bats Right                   0.215                                      0.250

So, when the players bats left 100 times,

The probability of hits he gets when faced by left-handed pitchers = 0.285 × 100 = 28.5

The probability of hits he gets when faced by right-handed pitchers = 0.175 × 100 = 17.5

Thus, the difference in the hits = 28.5 - 17.5 = 11

Hence, the player will get 11 more hits t when he faces left-handed pitchers as opposed to right-handed pitchers.

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From a recent company survey, it is known that the proportion of employees older than 55 and considering retirement is 8%. For a
Akimi4 [234]

Answer: 2.845

Step-by-step explanation:

The formula to find the standard deviation is given by :-

\sigma=\sqrt{n(1-p)p}, where p is the probability of getting success in each trial and n is the sample size.

Given : Sample size : n=110

The proportion of employees older than 55 and considering retirement : p=0.08

Then, the standard deviation is given by :-

\sigma=\sqrt{110(1-0.08)0.08}\approx2.845347079\approx2.845

Hence, the standard deviation for the sampling distribution of the sample proportions is 2.845.

3 0
2 years ago
If value of cos330° is √3/2 then find tan165°.
Umnica [9.8K]

Answer:

-2+sqrt(3)

Step-by-step explanation:

When cos(angle)=sqrt(3)/2

then sin(of that angle)= + or - 1/2 depending on the quadrant

Anyways 330 degrees is in the 4 quadrant.  Cosine is positive there while sine is negative.

so sin(330)=-1/2

Formula for tan(x/2)=(1-cos(x))/sin(x)

Therefore  tan(165)=tan(330/2)=(1-cos(330))/sin(330)=(1-sqrt(3)/2)/(-1/2)

Multiply top and bottom by 2 to get

tan(165)=(2-sqrt(3))/-1

tan(165)=-2+sqrt(3)

3 0
2 years ago
Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1
balandron [24]

Question:

Which statement is true about the discontinuities of the function f(x) = \frac{x-5}{3x^2-17x-28}

A)There are holes at x = 7 and .

B)There are asymptotes at x = 7 and .

C)There are asymptotes at x = –7 and .

D)There are holes at (–7, 0) and .

Answer:

B)There are asymptotes at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

Required:

Find the true statement

f(x) = \frac{x-5}{3x^2-17x-28}

We'll first factorize the denominator.

f(x) = \frac{x-5}{(3x+4)(x-7)}

Make x subject of the formula in (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

x = \frac{-4}{3}

x - 7

x = 7

Now check for the limit when (x = \frac{-4}{3}) and (x = 7)

lim f(x) when   (x = \frac{-4}{3}) = ±∞

lim f(x) when (x=7) = ±∞

Sinve they both make the denominator tend to zero, they are asymptotes

Therefore, there are asymptotes at (x = \frac{-4}{3}) and x=7

Option B is correct

6 0
2 years ago
Condense each expression. 5 log5 x - 1/4 log5 (8 -x)
allsm [11]

Step-by-step explanation:

5 log₅ x − ¼ log₅ (8−x)

log₅ x⁵ − log₅ (8−x)^¼

log₅ x⁵ − log₅ ∜(8−x)

log₅ (x⁵ / ∜(8−x))

4 0
2 years ago
Hannah has 127 books in her collection. Her school is hosting a book donation. There are z students at her school, and they each
luda_lava [24]

127 \div z
8 0
2 years ago
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