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Mice21 [21]
1 year ago
10

The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of

a wedding is $29,858 (XO Group website, January 5, 2015). Assume that the cost of a wedding is normally distributed with a mean of $29,858 and a standard deviation of $5600.
a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?
b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?
c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?
Mathematics
1 answer:
Maru [420]1 year ago
7 0

Answer:

0.0392,0.4709, 38083

Step-by-step explanation:

Given that XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of a wedding is $29,858

X is N(29,858, 5600)

Or Z=\frac{x-29158}{5600} is N*(0,1)

We can use std normal distribution table to get the probabilities

a) The probability that a wedding costs less than $20,000 (to 4 decimals)

= P(X

=0.0392

b) the probability that a wedding costs between $20,000 and $30,000

=0.5101-0.0392\\=0.4709

c) For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)

=29858+1.645*5600\\=38083

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Ok so 9(46) means 

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So 9*46 would be ur 1st way and ur 2nd would be 

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Check:- 

9*46=414
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Ans
9*46
46*9

Hope I helped:P



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