(9-5/5)*100= (4/5)*100 = 80% ( new height- original height /original height ) *100 the plant grew 80%
Answer:
11%
Step-by-step explanation:
it is a simple question, whenever you need to find % increase or % decrease.
always divide the increase as in this case $2 by the original amount which is $18 and multiply it by 100 as you need to take the %.
so,
2/18*100 gives you 11.11% * is multiply
Answer:
Store 3
Step-by-step explanation:
PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST
Number of toothpicks required per student = At least 9
Total number of students = 30
Number of toothpicks required for the entire class = At least 9 × 30 = At least 270
Number of toothpicks in the bag in the class storage room = 50
Additional number of toothpicks required to be bought to make sure there are enough toothpicks = 270 - 50 = 220
Hence, she needs to buy 220 toothpicks.
1. A straight line segment can be drawn joining any two points.
2. Any straight line segment can be extended indefinitely in a straight line.
3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.
4. All right angles are congruent.
5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.