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2 years ago

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The probability that a radish seed will germinate is 0.7. a gardener plants seeds in batches of 11. find the standard deviation

for the random variable x, the number of seeds germinating in each batch.

1 answer:

den301095 [7]2 years ago

3 0

To calculate for the standard deviation given the probability, we use the formula:

s = sqrt (n p q)

where s is standard deviation, n is number of samples = 11, p is probability of success = 0.7, q = 1 – p = 0.30

s = sqrt (11 * 0.7 * 0.3)

<span>s = 1.52</span>

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Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

2 years ago

What is the value of 6i/1+i? 2 – 6i 2 + 6i 3 – 3i 3 + 3i

mihalych1998 [28]

6i/ (1+i)

multiply by the complex conjugate (1-i)/(1-i)

6i/(1+i) * (1-i)/(1-i)

6i* (1-i) = 6i - 6i^2 = 6i - 6(-1) = 6i +6

(1+i)*(1-i)= 1-i +i -i^2 = 1 -i+i -(-1) = 1+1=2

(6+6i)/2

3+3i

Answer: 3+3i

6 0

2 years ago

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Which equation is the inverse of y = 9x2 – 4? y = StartFraction plus-or-minus StartRoot x + 4 EndRoot Over 9 EndFraction y = plu

andre [41]

Option C: $y=\pm\frac{\sqrt{x+4}}{3}$ is the inverse of the function

Explanation:

The given function is $y=9 x^{2}-4$

We need to determine the inverse of the function.

To determine the inverse of the function, we need to interchange the values of x and y and solve for y.

Let us interchange the variables x and y in the function $y=9 x^{2}-4$ , we have,

$x=9 y^{2}-4$

Adding both sides of the equation by 4, we have,

$x+4=9 y^{2}$

Dividing both sides of the equation by 9, we have,

$\frac{x+4}{9} =y^2$

Switch sides, we have,

$y^2=\frac{x+4}{9}$

Taking square root on both sides of the equation, we have,

$y=\pm\frac{\sqrt{x+4}}{3}$

Thus, the inverse of the function is $y=\pm\frac{\sqrt{x+4}}{3}$

Therefore, Option C is the correct answer.

8 0

2 years ago

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A bicycle manufacturer has a stock of 50 frames 70 wheels, and 120 reflectors. if each bicycle manufactured requires 4 reflector

Rainbow [258]

30 I think but this is probably a trick question so I'm just gonna assume I'm wrong.

5 0

2 years ago

The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The

ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. $150 + 51x < 100 + 55x$

b. $x > 12.5$

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

$Cost = \$100$

$Additional = \$55$ <em>(monthly)</em>

Second Phone;

$Cost = \$150$

<em /> $Additional = \$51$ <em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

$100 + 55x$

The second phone is expressed as:

$150 + 51x$

For the second to be less expensive that the first, the inequality is:

$150 + 51x < 100 + 55x$

Solving (b): Inequality Solution

$150 + 51x < 100 + 55x$

Collect Like Terms

$51x-55x$

$-4x$

Solve for x

$x > -50/-4$

$x > 12.5$

Solving (c): Interpret the solution in (b)

$x > 12.5$ implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

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2 years ago

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