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inna [77]
2 years ago
6

Mrs.thapa bought 150 kg of oranges.18 kg of oranges were rotten and not fit for selling.If she sold the remaining quantity of or

anges at the rate of Rs 80 per kg and gained 10%. Find the rate of cost price of oranges.
Help!!​
Mathematics
2 answers:
Dmitry_Shevchenko [17]2 years ago
8 0

Answer:

Rs64.00/kg  

Step-by-step explanation:

1. Calculate the amount of good oranges

Total amount of oranges    = 150 kg

Amount of rotten oranges =    18 kg

Amount of good oranges    = 132 kg

2. Calculate the income from  the good oranges

\text{Income} = \text{132 kg} \times \dfrac{\text{Rs80}}{\text{1 kg}} = \text{Rs10 560}

3. Calculate the net unit rate of income

The income from the good oranges was Rs10 560.

Based on 150 kg of oranges, the unit rate of income was

\text{Unit rate of income} = \dfrac{\text{RS10 560}}{\text{150 kg}} = \text{Rs70.40/kg}

4. Calculate the original unit rate of cost

Let x = original unit cost. Then

0.10x = 10 % of original unit cost and

1.10x = 10 % over original unit cost

1.10x = RS70.40/kg

        x = (RS70.40/kg)/1.10 = Rs64.00/kg

The original unit rate of cost was Rs64.00/kg.

kogti [31]2 years ago
3 0

Answer:

Rs.64

Step-by-step explanation:

<u>Amount of oranges:</u>

  • 150 kg

<u>Oranges sold:</u>

  • 150 - 18 = 132 kg

<u>Money made:</u>

  • 132* 80 = Rs. 10560

<u>Selling price of 150 kg:</u>

  • 10560/150 = Rs. 70.4

<u>Cost price:</u>

  • x+10% = 70.4
  • x*1.1= 70.4
  • x= 70.4/1.1
  • x= Rs.64
  • Cost price of oranges= Rs. 64
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Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

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0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]

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2 years ago
Two production lines produce the same parts per week of which 100 are defective. Line 2 produces 2,000 parts per week of which 1
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Answer:

(a) 0.0833 or 8.33%

(b) 0.40 or 40%

Step-by-step explanation:

Parts line one (n1) = 1,000 parts

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Parts line two (n2) = 2,000 parts

Defects line two (d2) = 150 parts

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The probability is 0.40 or 40%.

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Answer:

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Step-by-step explanation:

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