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2 years ago

What are two other ways to write 9(46)?

2 answers:

7 0

Ok so 9(46) means

9*46

So 9*46 would be ur 1st way and ur 2nd would be

46*9

Check:-

9*46=414
46*9=414

Ans
9*46
46*9

Hope I helped:P

Paul [167]2 years ago

4 0

9 x 46
46 x 9
X is multiplication symbol.

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What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one

Sav [38]

Answer:

<h2>2 and three-fourths </h2>

Step-by-step explanation:

Given the expression $\frac{11}{12}/\frac{1}{3}$ , the equivalent expression can be gotten as shown;

$= \frac{11}{12}/\frac{1}{3}\\= \frac{11}{12}*\frac{3}{1}\\ = \frac{11}{4} \\= 2+\frac{3}{4}\\ = 2\frac{3}{4}$

2 and three-fourth therefore gives the required expression

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2 years ago

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A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter

faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let c (t ) denote the amount of chlorine (in grams) in the tank at time t .

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(c (t )/(1000 + (10 - 25)t ) g/L) * (25 L/s) = 5c (t ) /(200 - 3t ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after t s there will be (1000 + 10t ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time t is (1000 - 15t ) L. Then the concentration of chlorine per unit volume is c (t ) divided by this volume.

So the amount of chlorine in the tank changes according to

$\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}$

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5t )^(5/3), then integrate both sides to solve for c (t ):

$\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0$

$\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0$

$\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0$

$\dfrac{c(t)}{(200-3t)^{5/3}}=C$

$c(t)=C(200-3t)^{5/3}$

There are 20 g of chlorine at the start, so c (0) = 20. Use this to solve for C :

$20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}$

$\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}$

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1 year ago

Leah claims the data in the table contains a cluster. why is leah’s statement true

Gre4nikov [31]

Answer:

Step-by-step explanation:

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2 years ago

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Greatest common factor of 88 and 48

kupik [55]

GFC is 8. Use a tree of 88 and 48. 88= 2^3 x 11 or 2 x 2 x 2 x 11

48=2^4 x 3 or 2 x 2 x 2 x 2 x 3 see how many groups count as the number once and multiply and bam GFC. Hope I helped! (:

4 0

2 years ago

If a large cylinder has a volume of 28260 cubic cm, how many cylinders can be filled out of the large cylinder if the small cyli

inysia [295]

Hi,

To find the number of small cylinders that fit inside the big cylinder. You need to divide volume of small cylinder with the volume of big cylinder. We do this by using formula to calculate volume of cylinder:

$v = \pi \times {r}^{2} \times h$

To find radius just divide diameter with 2.

$v = \pi \times {2}^{2} \times 6 \\ v = \pi \times 4 \times 6 \\ v = \pi \times 24 \\ v = 3.14 \times 24 \\ v = 75.4 {cm}^{3}$

Now just division:

$28260 \div 75.4 = 374.8$

Answer: You could fit 374.8 smaller cylinders inside a big cylinder.

Hope this helps.
r3t40

7 0

2 years ago