Answer:
it should be D....due to the fact that opposite over adjacent for the missing length
£87.00
Emily's dad pays 3 parts of the meal
Divide £52.20 by 3 to find one part of the ratio
= £17.40 ← 1 part of the ratio
2 parts = 2 × £17.40 = £34.80 ← Emily's share
total cost = £52.20 + £34.80 = £87.00
Answer:
$96 is the original price of book
Step-by-step explanation:
keep the unknown value as X
(19.2/X)*100 = 20%
19.2/X = 0.2
19.2/0.2 = X
X = 96
Answer:
the last option: 
Step-by-step explanation:
Make sure you have the numerical answer for each of the functional expressions that are shown among the possible solution choices:
f(4) = -14 (what the blue function reads [its y-value] when x is 4)
g(4) = 10 (what the red function reads [its y-value] for x=4)
g(-2) = 4 (y-value of the red function when x is -2)
f(2) = -8 (y-value of the blue function for x = 2)
f(-2) = 4 (y-value of the blue function for x =-2)
use them to compare the options they give you, and the only one that matches is the last option.
<h3>
Answer:</h3>
- f(x) = -2x^3 +3x^2 +11x -6
- see attached
- an infinite number. Since the magnitude of the leading coefficient is not specified, it may be any negative number. (We have chosen the smallest magnitude integer that makes all coefficients be integers.)
<h3>
Step-by-step explanation:</h3>
1. When "a" is a root of a polynomial, (x -a) is a factor of it. For the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).
In order to make the leading coefficient be negative, we need to multiply this product by a negative number. Any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.
Then ...
... f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)
... = -(2x² +3x -2)(x -3)
... = -(2x³ -3x² -11x +6)
... f(x) = -2x³ +3x² +11x -6
2. A graph created by the Desmos on-line graphing calculator is shown, and the zeros are highlighted.
3. As indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. You want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.