Answer:
la distancia del punto de observación A al incendio = 5.5 millas
la distancia del punto de observación B al incendio = 3.8 millas
Step-by-step explanation:
La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :
Del siguiente diagrama;
Usando la sine regla:


a sin 79 = 6 sin 63


a = 5.446 millas
la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)


b sin 79 = 6 sin 38


b = 3.7635 millas
la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)
Answer:
Lance will arrive at the airport at 10:00 AM.
Step-by-step explanation:
Lance left his house at 6:00 AM, and drove to the airport, which is 220 miles away, at 55mph; therefore, the time
it takes Lance to cover the distance of 220 miles is


Thus, it takes Lance 4 hours to reach the airport, and since he departed at 6:00 AM, he will arrive at the airport at (6+4):00 AM + 10:00 AM.
168/3 = 56
<em>Therefore, Chad is driving the car in 56 mph.</em>
672/56 = 12
<em>Therefore, Chad drives 672 miles in 12 hours.</em>
308/11 = 28
<em>Therefore, Chad drives 28 miles per gallon of gas.</em>
672/28 = 24
<em>Therefore, Chad uses 24 gallons of gas to drive 672 miles.</em>
Number 1 is -23 and number 2 is a