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aleksley [76]
2 years ago
12

Cylinder A has a volume of 360 cm3. Cylinder B has a base and height identical to that of cylinder B, but leans to the right in

such a way that its slant length is greater by 4 cm. What is the volume of cylinder B? V = 270 cm3 V = 360 cm3 V = 480 cm3 V = 600 cm3
Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0
I think the volume of cylinder B will be the same as that of cylinder A that is 360cm³
This is because the volume of the cylinder is dependent on the base and the perpendicular height, therefore, the slanting of the cylinder wont change its volume
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mojhsa [17]

Answer:

We have

$y=c(x)=\sqrt[3]{x} $

\text{for } x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729 \text{ and } 1

We have 10 points to find:

\text{Point A}(0, 0)

\text{Point B}(0.008, 0.2)

\text{Point C}(0.027, 0.3)

\text{Point D}(0.064, 0.4)

\text{Point E}(0.125, 0.5)

\text{Point F}(0.216, 0.6)

\text{Point G}(0.343, 0.7)

\text{Point H}(0.512, 0.8)

\text{Point I}(0.729, 0.9)

\text{Point J}(1, 1)

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2 years ago
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Inga [223]

Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

\dfrac{sin \  F}{f} = \dfrac{sin  \ A }{a}

\dfrac{sIn \  79}{6} = \dfrac{sin \   63}{a}

a sin 79 = 6 sin 63

a =\dfrac{6 \times sin \ 63}{sin \ 79}

a =\dfrac{6 \times 0.8910}{0.9816}

a = 5.446 millas

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\dfrac{sin \  F}{f} = \dfrac{sin  \ B}{b}

\dfrac{sin \  79}{6} = \dfrac{sin  \ 38}{b}

b sin 79 = 6 sin 38

b  = \dfrac{6 \times sin  \ 38}{sin \  79}

b  = \dfrac{6 \times0.6157 }{0.9816}

b = 3.7635 millas

la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

8 0
2 years ago
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Answer:

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