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Law Incorporation [45]
1 year ago
11

Given the values of the linear functions f (x) and g(x) in the tables, where is (f – g)(x) positive?

Mathematics
1 answer:
alexandr402 [8]1 year ago
4 0

Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9) .

----------------------

  • For the subtraction function, we simply subtract both functions, thus:

(f - g)(x) = f(x) - g(x)

  • It is positive if f is greater than g, that is: f(x) > g(x).
  • It is a linear function, so one function is greater before the equality, one after.
  • They are equal at x = 9.
  • If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:

(–∞, 9)

A similar problem is given at brainly.com/question/24610273

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4.5m is ____ % of 90 cm; 90 cm is ____ % of 4.5m
Burka [1]

Answer: 5%

Step-by-step explanation:

Firstly, Convert metre to centimetre

100cm = 1m

Therefore,

4.5m = 450cm

If 450cm is X% of 90cm

That becomes :

450= X% × 90

450= 90X%

X% = 450/90

X% = 5%

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2 years ago
Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete
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Answer:

Becky Did the Proof Wrong, since a Postulate is two adjacent angles that can be added to t=find the measure of another angle,

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Step-by-step explanation:

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2 years ago
Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The
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Step-by-step explanation:

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2 years ago
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8 0
1 year ago
Read 2 more answers
The vertices of rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0). what is the perimeter of the rhombus?
Harman [31]

Answer: 20 unit.

Step-by-step explanation:

Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).

Where, de, ef, fg, gd are sides of the rhombus defg.

By the distance formula,

de = \sqrt{(4-1)^2+(0-4)^2}

=\sqrt{3^2+4^2}

=\sqrt{9+16}

=\sqrt{25}

= 5

Thus, the side of rhombus = 5

By the property of rhombus,

de =  ef = fg = gd = 5 unit.

Thus, the perimeter of the given rhombus defg = de +  ef + fg + gd = 5+5+5+5 = 20 unit

6 0
2 years ago
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