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2 years ago

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Donna fed 1/11 of the chickens at a farm. Which decimal is equal to the fraction of chickens Donna fed? A. 0.09 B. 0.07 C. 0.01

D. 0.07

1 answer:

Lena [83]2 years ago

4 0

A. should be your answer because 1/11 is also equal to 0.090 repeating.

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Kali left school and traveled toward her friend’s house at an average speed of 40

ioda

Matt needs to travel 3 hours.
If 40km=1 hour
400km=? But there are two distances
200/40*1=5 hours
Therefore Kali needs to travel 5 hours to be 200 km away from the house.
If 50km=1 hour
200km=?
200/50*1hr=4hrs Therefore Matt needs to travel 4hrs to be 200 km away from the house. But Kali traveled 1hr earlier than Matt. 4hrs-1hr=3hrs
Therefore Matt has to travel for 3 hours to be 400km away from Kali.

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2 years ago

I have a hat that contains six nickels and five pennies. I draw coins from the hat at random, without replacement. Find the prob

Rzqust [24]

6 nickels and 3 pennies

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1 year ago

A function f on [a, b] is called a step function if there exists a partition P = {a = u0 < u1 < ··· < cm = b} of [a, b]

Arturiano [62]

Answer:

IDK

Step-by-step explanation:

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2 years ago

A machine fills boxes weighing Y lb with X lb of salt, where X and Y are normal with mean 100 lb and 5 lb and standard deviation

Bas_tet [7]

Answer:

Option b. None is the correct option.

The Answer is 63%

Step-by-step explanation:

To solve for this question, we would be using the z score formula

The formula for calculating a z-score is given as:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

We have boxes X and Y. So we will be combining both boxes

Mean of X = 100 lb

Mean of Y = 5 lb

Total mean = 100 + 5 = 105lb

Standard deviation for X = 1 lb

Standard deviation for Y = 0.5 lb

Remember Variance = Standard deviation ²

Variance for X = 1lb² = 1

Variance for Y = 0.5² = 0.25

Total variance = 1 + 0.25 = 1.25

Total standard deviation = √Total variance

= √1.25

Solving our question, we were asked to find the percent of filled boxes weighing between 104 lb and 106 lb are to be expected. Hence,

For 104lb

z = (x-μ)/σ,

z = 104 - 105 / √25

z = -0.89443

Using z score table ,

P( x = z)

P ( x = 104) = P( z = -0.89443) = 0.18555

For 1061b

z = (x-μ)/σ,

z = 106 - 105 / √25

z = 0.89443

Using z score table ,

P( x = z)

P ( x = 106) = P( z = 0.89443) = 0.81445

P(104 ≤ Z ≤ 106) = 0.81445 - 0.18555

= 0.6289

Converting to percentage, we have :

0.6289 × 100 = 62.89%

Approximately = 63 %

Therefore, the percent of filled boxes weighing between 104 lb and 106 lb that are to be expected is 63%

Since there is no 63% in the option, the correct answer is Option b. None.

3 0

2 years ago

Abbey wants to use her savings of $1,325 to learn yoga. The total charges to learn yoga include a fixed registration fee of $35

Brums [2.3K]

So for this, this can be written into the equation $y=50x+35$ (x = number of months, y = total cost).

To solve this problem, we need to plug in 1325 into the y-variable and solve from there.

$1325=50x+35$

Subtract 35 on each side to get $1290=50x$

Then just divide by 50 on each side, and your answer should be $25.8=x$

And because we cannot go past budget, we will have to round down to 25. In context, the maximum amount of months Abbey can do is 25 months.

8 0

2 years ago

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