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kobusy [5.1K]
2 years ago
9

Cameron buys 2.45 pounds of apples and 1.65 pounds of pears. Apples and pears each cost c dollars per pound. If the total cost a

fter using a 75 cents off entire purchase shown $4.12, write an equation that can be used to find the value of c.
Mathematics
1 answer:
Leto [7]2 years ago
7 0

Answer:

2.45c + 1.65c = 4.12 + 0.75

Step-by-step explanation:

To write an equation to find the value for c, we need to declare what c is first.

c = price of fruit

2.45c + 1.65c = 4.12 + 0.75

Now we multiplied c to 2.45 and 1.65 and added them together, because whatever the value of c is will give us the equivalence of the sum of 4.12 + 0.75.

Now to check if the equation is right, let's solve for c.

2.45c + 1.65c = 4.12 + 0.75

4.1c = 4.87

Now to get the value of c, we divide both sides of the equation by 4.1.

\dfrac{4.1c}{4.1}=\dfrac{4.87}{4.1}

c = 1.19

Now let's substitute the value of c in the equation to see if we got it right.

2.45(1.19) + 1.65(1.19) = 4.12 + 0.75

2.92 + 1.96 = 4.87

4.87 = 4.87

Therefore concluding that the value of c is 1.19.

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6 0
2 years ago
When finding statistical measures of sampling distributions some measures of biased which of the following represents a by stati
Lerok [7]

Answer:median

Step-by-step explanation:

i just took the test and that was the correct answer for me

6 0
2 years ago
Please... Solve this: the bearing of a tree from a house is 295°. Find the bearing of the house from the tree.
jonny [76]

Given parameters:

Bearing of the tree from the house  = 295°

Unknown:

Bearing of the house from the tree = ?

Solution:

This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.

To find the back bearing in this regard, simple deduct the forward bearing from 360°;

    Backward bearing  = 360° -295°

                                    = 65°

The bearing from house to the tree is 65°

4 0
2 years ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8
Orlov [11]

Answer: no Tony is not correct It is less than 5 hundred dollars.

Step-by-step explanation: 8×37=296 +200 = 496

4 0
2 years ago
Read 2 more answers
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