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gizmo_the_mogwai [7]
2 years ago
5

When finding statistical measures of sampling distributions some measures of biased which of the following represents a by stati

stical measure
A. Median

B. Variance

C. Mean

D. Proportion
Mathematics
1 answer:
Lerok [7]2 years ago
6 0

Answer:median

Step-by-step explanation:

i just took the test and that was the correct answer for me

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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
nikitadnepr [17]
Year         Sam              Sally1:             X                    (3/2)X-10002:            (5/2)X-2000     2X-15003:             X/5+1000       X/4+1400Total         37X/10-1000    15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.
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2 years ago
In a survey respondents were asked which type of movie they watched most often. the bar graph shows how many males and how many
Y_Kistochka [10]
Males that watched action movies : 13
males that watched drama movies : 5

so there are (13 - 5) = 8 more that watched action then drama
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2 years ago
Read 2 more answers
Given: m || n, ∠1 ≅ ∠3 Prove: p || q Horizontal parallel lines n and m are cut by transversals q and p. At the intersection of l
dimaraw [331]

Answer:

Angle 1 congruent to angle 2

Transitive property

Converse corresponding angles theorem

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2 years ago
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The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample
wariber [46]
Given:
standard deviation = 4.3%
sample size = 15
mean = 26.4%

error = σ/√n

error = 4.3% / √15

error = 4.3% / 3.873

error = 0.0111

0.0111 x 100% = 1.11%
4 0
2 years ago
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A random sample of 25 roundtrip flights between Philadelphia and Dallas has an average airfare of $393.50 with a sample standard
Sauron [17]

Answer:

$393.50+/-$19.72

= ( $373.78, $413.22)

Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $393.50

Standard deviation r = $50.30

Number of samples n = 25

Confidence interval = 95%

z value(at 95% confidence) = 1.96

Substituting the values we have;

$393.50+/-1.96($50.30/√25)

$393.50+/-1.96($10.06)

$393.50+/-$19.7176

$393.50+/-$19.72

= ( $373.78, $413.22)

Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)

5 0
2 years ago
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