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klemol [59]
1 year ago
15

The ratio of the sides of two squares is 3:1. what is the ratio of their perimeters?

Mathematics
1 answer:
inessss [21]1 year ago
6 0
Your answer would be 3:1



hoped this helped
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∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′.
RideAnS [48]

Answer:

The coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).

Step-by-step explanation:

From the figure it is clear that the coordinates of triangle are A(0,0), B(1,3) and C(1,1).

∆ABC is translated 2 units down and 1 unit to the left.

(x,y)\rightarrow (x-1,y-2)

A(0,0)\rightarrow (0-1,0-2)=(-1,-2)

B(1,3)\rightarrow (1-1,3-2)=(0,1)

C(1,1)\rightarrow (1-1,1-2)=(0,-1)

Then it is rotated 90° clockwise about the origin to form ∆A′B′C′.

(x,y)\rightarrow (y,-x)

(-1,-2)\rightarrow A'(-2,1)

(0,1)\rightarrow B'(1,0)

(0,-1)\rightarrow C'(-1,0)

Therefore the coordinates of image are A'(-2,1), B'(1,0) and C'(-1,0).

7 0
1 year ago
Which description best compares the graphs of the two functions below?
Pavlova-9 [17]
Some of your pic is cut off so it's difficult to give the exact answer.  But if you plot the points from the table you get that the equation for that set of data is linear and is y = 1/3x -2.  This tells me that the y-intercepts are the same for both equations, so your answer is not the first or the third.  Because the slope of the function A is 3 and for B is 1/3, the line for function A is steeper, the second of your choices above.
7 0
2 years ago
Read 2 more answers
Lisa says that the indicated angles cannot have the same measure. Marita disagrees and says she can prove that they can have the
AlexFokin [52]
I agree with Marita, that the angles could have the same measure.  This can be proven if you set the two amounts equal and solve for x. 

9x - 25 + x = x + 50 + 2x - 12

To begin, we should combine like terms on both sides of the equation to start simplifying the equation.

10x - 25 = 3x + 38

Next, we should subtract 3x from both sides and add 25 to both sides to get the variable x alone on the left side of the equation.

7x = 63

Finally, we should divide both sides by 7, to get rid of the coefficient of x.

x = 9

If you plug in 9 for x in our first equation, you get that both of the angle measurements equal 65 degrees.  This means that Marita is correct, because if x = 9, then the angles would have the same measure.


8 0
1 year ago
If LN=54 and LM=31, find MN
kirza4 [7]
In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN. 

The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
             LN + LM = MN

We are given with the lengths of the smalller segments and substituting the known values,
             MN = 54 + 31
            MN = 85

<em>ANSWER: MN = 85</em>
7 0
1 year ago
Read 2 more answers
Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.
Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

A=\frac{3\sqrt{3} }{2} r^2

Where r is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid:A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2

From these areas we find the radius of the hexagons:

r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}

r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that r_1 r_2 form similar triangles with length H

Therefore we have:

\frac{H-8}{r_1} =\frac{H}{r_2}

We put in the numerical values of r_1, r_2 and solve for H:

\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}

8 0
2 years ago
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