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Diano4ka-milaya [45]
2 years ago
5

A box in a college bookstore contains books and each book in the box is a history book and english book or a science book . if 1

/3of these books are history books and 1/6 are english books what fraction of the books are science books
Mathematics
2 answers:
harina [27]2 years ago
5 0

Answer:

1/2 of the books are science books because once you convert the other two books you get 2/6 +1/6= 1/2 so the science books will be the other half.

Step-by-step explanation:

inessss [21]2 years ago
4 0
1/2 of the books are science books because once you convert the other two books you get 2/6 +1/6= 1/2 so the science books will be the other half.
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Ben Carson was loaned $125.00 to pay $6.00 interest for $100.00 every week ,after 3 weeks how much do he pay back to clear the d
Ghella [55]

Answer:

Total amount pay after 3 week = $147.5

Step-by-step explanation:

Given:

Amount of loan taken = $125

Amount interest per $100 = $6 per week

Find:

Total amount pay after 3 week

Computation:

Amount of interest per week = 125[6/100]

Amount of interest per week = $7.5 per week

Amount of interest in three week = 3 x Amount of interest per week

Amount of interest in three week = 3 x 7.5

Amount of interest in three week = $22.5

Total amount pay after 3 week = Amount of loan taken + Amount of interest in three week

Total amount pay after 3 week = 125 + 22.5

Total amount pay after 3 week = $147.5

8 0
2 years ago
A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
2 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?
Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

x = - 3 ± √9 - 4(- 16)]/2×2

x = [- 3 ± √9 + 64]/2×2

x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

x = (-3 + 8.544) /4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

8 0
2 years ago
Read 2 more answers
Match each three-dimensional figure to its volume based on the given dimensions. (Assume π = 3.14.)
LekaFEV [45]

Answer:

The volume of the cylinder is 150.72 cm³ ⇒ last answer

The volume of the cone is 314 cm³ ⇒ 1st answer

The volume of the pyramid is 160 cm³ ⇒ 2nd answer

The volume of the pyramid is 48 cm³ ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the volumes of some shapes

- The volume of the cylinder of radius r and height h is:

 V = π r² h

- The volume of the cone of radius r and height h is:

 V = 1/3 π r² h

- The volume of the pyramid is:

 V = 1/3 × its base area × its height

* Lets solve the problem

# A cylinder with radius 4 cm and height 3 cm

∵ V = π r² h

∵ π = 3.14

∵ r = 4 cm , h = 3 cm

∴ v = 3.14 (4)² (3) = 150.72 cm³

* The volume of the cylinder is 150.72 cm³

# A cone with radius 5 cm and height 12 cm

∵ V = 1/3 π r² h

∵ π = 3.14

∵ r = 5 cm , h = 12 cm

∴ V = 1/3 (3.14) (5)² (12) = 314 cm³

* The volume of the cone is 314 cm³

# A pyramid with base area 16 cm² and height 30 cm

∵  V = 1/3 × its base area × its height

∵ The area of the base is 16 cm²

∵ The height = 30 cm

∴ V = 1/3 (16) (30) = 160 cm³

* The volume of the pyramid is 160 cm³

# A pyramid with square base of length 3 cm and height 16 cm

∵  V = 1/3 × its base area × its height

∵ The area of the square = s²

∵ The area of the base = 3² = 9 cm²

∵ The height = 16 cm

∴ V = 1/3 (9) (16) = 48 cm³

* The volume of the pyramid is 48 cm³

3 0
2 years ago
Read 2 more answers
Ray Np is an angle bisector of angle MNQ and measure of Angle PNQ = 2x+1. Find the measure of angle MNQ. If The measure of MNQ=x
Step2247 [10]
Refer to the diagram below.

Because ray NP bisects ∠MNQ, therefore
∠MNP = ∠PNQ = 2x + 1.
Therefore
∠MNQ = 2*∠PNQ = 2(2x + 1) = 4x + 2.

Because ∠MNQ is given as x² - 10, therefore
x² - 10 = 4x + 2
x² - 4x - 12 = 0
(x + 2 )(x - 6) = 0
x = -2, or x = 6

When x = -2, 
∠MNQ = 4*(-2) + 2 = -6°
This answer is not acceptablle, therefore x = -2 should be rejected.

When x = 6,
∠MNQ = 4*6 + 2 = 26°

Answer: x = 6, and ∠MNQ = 26°

7 0
2 years ago
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