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FrozenT [24]
1 year ago
8

A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​

Mathematics
1 answer:
Leno4ka [110]1 year ago
7 0

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

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Answer:

They are perpendicular because they have slopes that are opposite reciprocals of −2 and one half.

Step-by-step explanation:

This is because x = -2 and half of -2 is 1

when we use CD line and x2 we find 8x+4y=16 when added to 2x -4y=8 would equal 10x+4y = 2 1/2 xy = 16

When we use for AB line we see they are perpendicular 2 1/2 x 2 = 5 -4y = 8 shows y to be -2 and the 1/2 line leaves -2 1/2 and x also is 2 1/2.

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1 year ago
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A safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability that the
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Answer:

The probability is found:

P = 24/3024 = 1/126

Step-by-step explanation:

To find total number of outcomes, we have to find permutation of 9 things taken 4 at a time:

P(9,4) = 9! / (9-3)!

P(9,4) =362880/120

P(9,4) = 3024

Number of even numbers from 0 to 9 = 4

To find desirable number of outcome, find permutation of 4 things taken 4 at a time.

P(4,4) = 4! / (4-4)!

P(4,4) = 24/1

P(4,4) = 24

The probability that the lock consists of all even digits is

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2 years ago
Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep
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<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. 3x+6y-12z=36

2. x+2y-4z=12

3. 4x+8y-16z=48

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with x+2y-4z=12 which is the same as the equation number 2.

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1 year ago
FOR 14 POINTS Thalia, a quiz show contestant, answered 20 questions. She was awarded 2 points for every correct answer that she
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Answer:

<em>The viewer mistakenly determined that one of the equations in the system should be 2 x + y = 28. Instead modifications should have been made before applying the equation.</em>

Step-by-step explanation:

Given

Total Questions = 20

Total Points = 28

Correct Answers = +2 points

Incorrect Answers = -1 point

Required

Spot the error in the viewer's calculation

The viewer represents the correct answers with x and the incorrect ones with y.

This implies that

x + y = 20

Also, for every correct answers, she gets 2 points;

<em>This can be represented by 2x</em>

and for every incorrect answers, she gets -1 point

<em>This can be represented by -y</em>

This implies that

2x - y = 28

This is where the viewer made a mistake

The viewer's mistake is that; instead of subtracting total incorrect points from the correct points, the viewer added them together;

Solving further

2x - y = 28

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\frac{3x}{3} = \frac{48}{3}

x = \frac{48}{3}

x = 16

Substitute x = 16 in x + y = 20

16 + y = 20

Subtract 16 from both sides

16 - 16 + y = 20 - 16

y = 20 - 16

y = 4

<em>This implies that the contestant answered 16 questions correctly and 4 questions incorrectly</em>

<em></em>

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