A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?
1 answer:
the upper bound for the length is .
<u>Step-by-step explanation:</u>
Lower and Upper Bounds
- The lower bound is the smallest value that will round up to the approximate value.
- The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is .
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Answer:
Boat traveled 553.24 feet towards the lighthouse.
Step-by-step explanation:
In the figure attached AB is the light house of height 200 feet.
Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'
so 1' = degree
so angle of elevation at point C = 14 +
So angle of elevation from C = (14 + 0.87) = 14.87°
Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + = 45.17°
Now we have to calculate the distance CD, traveled by the boat.
In ΔABC
tan14.87 =
0.2655 =
BC =
BC = 753.239 feet
Similarly in ΔABD
tan45.17 =
1 =
BD = 200 feet
So distance CD = BC - BD
CD = 753.239 - 200
= 553.24 feet
Therefore, Boat traveled 553.24 feet towards the lighthouse.
Answer:
Step-by-step explanation:
Previous concepts
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:
And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:
Or equivalently:
Solution to the problem
For this case we are interested in the total T, and we can find the mean and deviation for this like this:
If we solve for T we got:
And the expected value is given by:
And we can find the variance like this:
And then the deviation is given by:
And the distribution for the total is:
And we want to find this probability:
And we can use the z score formula given by:
And replacing we got this: