Evaluate 6+3b if b=7

2 answers:

6 0

27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.

Wittaler [7]2 years ago

5 0

Evaluate 6+3b if b=7
To solve this problem, we must plug the value of b into the equation and follow the order of operations like so:
Original Equation: 6+3b
Plug in Given Information: 6+3*7
Remember that in the order of operations, we multiply before adding.
Multiply: 6+21
Add: The answer is <u>27.</u>

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Crude oil Imports to one country from another for 2009-2013 could be approximated by the following model where t is time in year

Mashutka [201]

Answer:

Time = approximately mid 2012
Oil import rate = 3600 barrels

Step-by-step explanation:

<h3><em>Unclear part of the question</em></h3>

I(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13)
According to the model, approximately when were oil imports to the country greatest? t = ?

<h3>Solution</h3>

Given the quadratic function

<em>The vertex of a quadratic function is found by a formula: x = -b/2a</em>

<u>As per given function:</u>

b = 800, a = -35

t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13

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<u>Considering this in the function, to get oil import rate for the same time:</u>

l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285

<u>Rounded to two significant figures, the greatest oil import rate was</u>:

3600 barrels

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Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 400 seconds a

garri49 [273]

Answer:

Step-by-step explanation:

In the normal distribution curve, the mean is in the middle and each line to the left and to the right of that mean represent 1- and 1+ the standard deviation. If our mean is 400, then 400 + 50 = 450; 450 + 50 = 500; 500 + 50 = 550. Going from the mean to the left, we subtract the standard deviation and 400 - 50 = 350; 350 - 50 = 300; 300 - 50 = 250. We are interested in the range that falls between 350 and 450 as a percentage. That range represents the two middle sections, each containing 34% of the data. So the total percentage of response times is 68%. We are looking then for 68% of the 144 emergency response times in town. .68(144) = 97.92 or 98 emergencies that have response times of between 350 and 450 seconds.