By plugging (k-2) in t, we can write that
Answer:
The herbicide has no impact on fish
Step-by-step explanation:
Experimental research includes to divide the concerned group 'fishes' here into 'treatment' & 'control' group, to study impact of a treatment. Hypothesis test the statistical significance of propositions. Null hypothesis signifies no impact, alternate hypothesis signifies impact.
Let averages enzyme level of treatment & control be Xt & Xc
- Null Hypothesis [H0] : Xt = Xc, or Xt - Xc = 0
- Alternate Hypothesis [H1] : Xt ≠ Xc, or Xt - Xc ≠ 0
If hypothesis test suggests that there is no significant difference between treatment & control group enzyme level, so we reject H0 & accept H1. It implies that the herbicide has no significant impact on fishes enzymes.
Answer:
Suzie walks faster by 0.27 miles per hour.
Step-by-step explanation:
Addie walked 
miles in 45 minutes and Suzie covered 
miles in 
of an hour.
So, Addie walked 2.5 miles in 45 minutes i.e. 
hours.
Therefore, the walking speed of Addie is 
miles per hour.
Again, Suzie covered i.e. 2.4 miles in i.e. 0.67 hours.
So, the walking speed of Suzie is 
miles per hour.
Hence, Suzie walks faster by (3.6 - 3.33) = 0.27 miles per hour. (Answer)
n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
