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drek231 [11]
2 years ago
8

Diane reed had office supply sales of $3,285 this month. this is a 78% of last months supply sales. what was the amount of last

years sale?
Mathematics
1 answer:
Hoochie [10]2 years ago
8 0

To solve this problem, we can set up an equation, letting the unknown value of last month's supply sales be represented by the variable x.

First, we must convert 78% to its decimal equivalent, by dividing 78/100. This is because percentages are parts of a whole 100 percent.

78/100 = 0.78

Now, we are ready to set up our equation, using our knowledge that the word "of" refers to multiplication in mathematics.

3,285 = 0.78x

To solve our equation, we must divide both sides of the equation by 0.78 to get the variable x alone on the right side of the equation.

x = 4211.53846154

This means that last month's supply sales were about $4,211.54 (we round the last digit up because 8 is greater than 5).

Hope this helps!


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A man spent 15/16 of his entire fortune in buying a car $7500. How much money did he possess?
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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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