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Aleksandr [31]
2 years ago
9

If a = 0.6 repeating and b = 0.75, then a x b = blank and a/b = blank

Mathematics
1 answer:
atroni [7]2 years ago
8 0

Answer:

a*b = 1/2

a/ b = 8/9

Step-by-step explanation:

a = 0.66666  and b = 0.75

To multiply it we write the decimal numbers in fraction form

a= 0.666666...

Multiply by 10 on both sides

10 a = 6.66666...

    a = 0.66666...

Subtract the second equation

9a = 6

divide by 9 on both sides

a=\frac{6}{9}=\frac{2}{3}

so 0.6666 = 2/3

Now we convert 0.75 into fraction form

0.75=\frac{0.75}{1}

Multiply top and bottom by 100 to remove decimal

\frac{75}{100} = \frac{3}{4}

so 0.75 is 3/4

a= 2/3  and b = 3/4

a*b = \frac{2}{3} * \frac{3}{4} = \frac{6}{12} = \frac{1}{2}

\frac{a}{b} = \frac{\frac{2}{3}}{\frac{3}{4}} = \frac{2}{3} * \frac{4}{3} =\frac{8}{9}


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Answer:

He burnt 1000 calories per hour when playing basketball.

Step-by-step explanation:

Let B be calories burned playing basketball, and C calories burned canoing.

1800 = B + 2C

3200 = 2B + 3C

From 1st equatipn, we get that B = 1800 - 2C

Replacing into the 2nd equation, we have:

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2 years ago
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A school district has a student population of $6,734 students. If the maximum class size is 25 students. How many more teacher m
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Answer:

53 teachers

Step-by-step explanation:

Basically, what we need to do here is to find how many teachers there need to be, first. If there are 6,734 students in the school district and if maximum class size is 25, then the number of teachers needed is:

6,734 / 25 = 269.36

Of course, it's obvious that we can't have a decimal number of teachers, so we need to find integer (269 or 270).

If we take 269 teachers and 25 students per class, we get:

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An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
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Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

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h_0 = Initial height.

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s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

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