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frez [133]
1 year ago
7

A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo

u need to replace the guy wire on a pole that is 20 feet tall.. The anchor point for this flagpole is 15 feet away from the base of the pole. a. How long is the wire you need to purchase to replace the old wire? b. You are also helping a friend determine the length of a guy wire for a 10-foot flagpole. The wire needs to be anchored 6 feet from the base of the pole. You can purchase guy wires in whole foot lengths only. Using your knowledge of perfect squares, estimate the length of wire you would need to complete the project. How much wire would be left over?

Mathematics
1 answer:
r-ruslan [8.4K]1 year ago
8 0

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

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Answer:

Option C is correct.

Ratio of longer leg to hypotenuse is;  \sqrt{3} : 2

Step-by-step explanation:

This is the special right angle triangle 30°-60°-90°  as shown below in the figure.

  • The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
  • The side opposite the 60° angle will be the longer leg, because 60 degrees is the mid-sized degree angle in this triangle.
  • Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.

In 30°−60°−90° right triangle,

  • the length of the hypotenuse is twice the length of the shorter leg,also
  • the length of the longer leg is \sqrt{3} times the length of the shorter leg.

Then:

the sides are in proportion i.e,  1:\sqrt{3} :2

Therefore, the ratio of the length of the longer leg to the length of its hypotenuse is:  \sqrt{3} : 2



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The experimental probability that Kevin will catch a fly ball is equal to 7/8. About what percent of the time will Kevin catch a
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Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi
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Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

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