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frez [133]
2 years ago
7

A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo

u need to replace the guy wire on a pole that is 20 feet tall.. The anchor point for this flagpole is 15 feet away from the base of the pole. a. How long is the wire you need to purchase to replace the old wire? b. You are also helping a friend determine the length of a guy wire for a 10-foot flagpole. The wire needs to be anchored 6 feet from the base of the pole. You can purchase guy wires in whole foot lengths only. Using your knowledge of perfect squares, estimate the length of wire you would need to complete the project. How much wire would be left over?

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
8 0

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

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Answer:

<em><u>The final atmospheric pressure is 5.19 · 10⁴ Pa</u></em>

Step-by-step explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

pV = const.

where p is the gas pressure and V is the volume

The equation can also be rewritten as

p₁ V₁ = p₂ V₂

where in our problem we have:

p₁ = 1.03 · 10₅ Pa is the initial pressure (the atmospheric pressure at sea level)

V₁ = 90.0L is the initial volume

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V₂ = 175.0L is the final volume

Solving the equation for p2, we find the final pressure:

p₂ = p₁ v₁ divided by V₂ = (1.01 · 10⁵)(90.0) divided by 175.0 = 5.19 · 10⁴ Pa

8 0
2 years ago
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A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between
Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

y(x) = 25,000*0.95^x

In the first year the value of the printer is:

y(1) = 25,000*0.95^1 = 23,750

On the second year the value of the printer is:

y(2) = 25,000*0.95^2 = 22,562.5\\

On the third year the value of the printer is:

y(3) = 25,000*0.95^3 = 21,434.38\\

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0
2 years ago
A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (4, 7). What is
PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

The vector in component form is the difference of the coordinates of its end points:

  rock - ship = (4, 7) - (1, 0) = (3, 7) . . . . vector from ship to rock

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The angle from North can be found using the tangent relation:

  tan(bearing) = (east distance)/(north distance) = 3/7

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The bearing of the rock is 23.20°.

3 0
2 years ago
shelly is going shopping at the mall to buy three pairs of shoes. she has a coupon for $2 off per pair of shoes after buying the
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Okay, to start, we can multiply the $2 coupon by two because that is the amount of pairs she is going to by. So it would be $4 off. Now, if all of the shoes she purchased the same price, this is made a little easier. We can simply take $80 and $122 and add it by the $4 discount. Our new numbers would be $84 and $126. Now in order for this to work we would want all the numbers to be the same. We take $84 and divide it by three pairs, to get the values. For the least amount she can spend per pair is $28 and the most amount she can spend per pair is $42. 
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alina1380 [7]

Answer:

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b) The set of all rational numbers intersected with [0, 1] (i.e,) Q ∩ [0,1]

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c) The Cantor set: Not compact. The sequence (1,2,3, . . .) has no convergent subsequences.

d) (1+1/2.2+1/3.2+....+1/n2: n>=1):

Not compact. The sequence (1/2,1/3,1/4, . . .) consists of elements of the set, but the sequence (and, thus, any subsequence) converges to 0, which is not in the set.

e) {1, 1/2, 2/3, 3/4, 4/5, 5/6, . . . }:

The sequence {1,1/2,2/3,3/4,4/5, . . .} is compact.

7 0
2 years ago
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