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frez [133]
2 years ago
7

A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo

u need to replace the guy wire on a pole that is 20 feet tall.. The anchor point for this flagpole is 15 feet away from the base of the pole. a. How long is the wire you need to purchase to replace the old wire? b. You are also helping a friend determine the length of a guy wire for a 10-foot flagpole. The wire needs to be anchored 6 feet from the base of the pole. You can purchase guy wires in whole foot lengths only. Using your knowledge of perfect squares, estimate the length of wire you would need to complete the project. How much wire would be left over?

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
8 0

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

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The condo costs $163,000, earns $2,986 per month, spends no more than 25% of her income, then if she pays $33,000 for the down payment, the remaining amount would be $130,000. Since 20% of the initial cost is only $32,600, she can adjust her down payment to 20.25% of the initial cost so that the annual payments would be less.
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Lamar shares 6 pencils equally with himself and 5 friends. Write an equation and solve to show the number of pencils each friend
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6 pencils÷ lamer+5 other friends=1.1 pencil for each person
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2 A pharmacist has a 13 % alcohol solution and another 18 % alcohol solution. How much of each must he use to make 50 grams of a
nalin [4]
<h2>Therefore he took 40 gram of 1^{st} type solution and 10 gram of 2^{nd} type solution.</h2>

Step-by-step explanation:

Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of 1^{st} type solution

and he took (50-x) gram of 2^{nd} type solution.

Total  amount of alcohol =[x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ] gram

Total amount of solution = 50 gram

According to problem

⇔\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}

⇔\frac{13x +900-18x}{100\times50} =\frac{14}{100}

⇔- 5x= 700 - 900

⇔5x = 200

⇔x = 40 gram

Therefore he took 40 gram of 1^{st} type solution and (50 -40)gram = 10 gram of 2^{nd} type solution.

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How do you this question? Please help.
dangina [55]
N - Nicholes money
M - Marys money

(1) N + M = 4800 ⇒ N = 4800 - M
(2) N - 800 = M - 2/5M ⇒ N - 800 = 3/5M

subtitute (1) to (2)

4800 - M - 800 = 3/5M
4000 - M = 3/5M
-M - 3/5M = -4000
-8/5M = -4000  |multiply both sides by (-5/8)
M = 2500

subtitute the value of M to (1)

N = 4800 - 2500
N = 2300

Answer: Mary had at first $2500. (Nichole: $2300).
5 0
2 years ago
Ramona's backyard is fenced and represented by parallelogram YARD with measures in meters. She installed a 12-meters fence to se
Alisiya [41]
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we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2

lets expand:
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substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
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substitute in the fence equation:
x^2 = 81 - y^2
x^2 = 81 - 5.4^2
x = 7.2 m that is the length of the fence



3 0
2 years ago
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