Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
The Rome data center is best described by the mean. The New York data center is best described by the median
Step-by-step explanation:
Before moving forward, first we should understand that what is mean and median. Mean is the average of all the values in the data set. Median is the middle value of the data set in ascending order. As we noticed that there is an outlier in the data for NEW YORK (An outlier is an extreme value in the data set which is much higher or lower as compared to other numbers. It affects the mean value). Since outlier is found in the data of New York therefore mean is not a good representation on the central tendency of the data and gets distorted by the outlier. Therefore it is better to use median. While Rome does not have any outlier, so we can use mean for this.
Therefore we can say that the Rome data center is best described by the mean. The New York data center is best described by the median.
Thus option C is correct....
We are asked to solve for:
P (sand | positive)
So, we solve this by:
P (sand | positive) = P (sand) x P (positive for sand)
P (sand | positive) = 0.26 (0.75)
P (sand | positive) = 0.195
The probability is 0.195 or 19.5%.
Your answer would be B and C
Answer:
Step-by-step explanation:
Since a large ice chest holds the water = 62 liters
And smaller chest holds the water = 
of the larger ice chest
= 
= 
liters
Therefore, fraction that represents the amount of ice water in the smaller ice chest will have 0 in the first box, 248 in the numerator and 5 in the denominator.
