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viva [34]
2 years ago
13

The lines below are perpendicular. If

Mathematics
1 answer:
RSB [31]2 years ago
5 0

Answer:

Correct answer: s₁ = - 2

Step-by-step explanation:

The relationship between the slope of two lines that are perpendicular is:

s₁ = - 1/s = - 1/(1/2) = - 2

God is with you!!!

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The college has 700 students, and has issued student 388 parking permits. What is the percentage of students with parking permit
andreyandreev [35.5K]

55.4% ( to 1 decimal place )

to find percentage, make a fraction with parking permits issued on numerator and total students on denominator then multiply by 100%

percent of students with parking permits = \frac{388}{700} × 100% = 55.4%


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2 years ago
This diagram shows triangles ABC and PQR. ABC is mapped to PQR by combining two single transformations. The first is a rotation
dedylja [7]

Answer:

enlarge by -2 by centre point (3,1)

Step-by-step explanation:

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What are the domain and range of function p within the context of Melissa's garden?
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Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

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The diagram shows JKL. Which term describes point M?
laiz [17]

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A; Orthocenter

Step-by-step explanation:

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