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VLD [36.1K]
2 years ago
10

Ron is a basketball coach. The table shows the height in inches of the players Ron coaches

Mathematics
1 answer:
n200080 [17]2 years ago
7 0
Range from 68 inches to 76 inches
Tallest player is 76 inches
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Consider the curve y = x − x3. (a) Find the slope of the tangent line to the curve at the point (1, 0). (b) Find an equation of
Katena32 [7]

Answer:

a) mt = -2

b) y=2-2x

Step-by-step explanation:

We have y=x-x^{3}  ⇒  f(x)=x-x^{3} and we must find

a) The slope of the tangent line to the curve at the point (1,0)

b) The equation of the tangent line in part (a)

a) f(x)=x-x^{3} with the point (1,0) then f'(x) =1-3x^{2} the slope (mt) in x=1 is

f'(1)=1-3(1^{2})=1-3=-2  ,  m t= -2

b) mt=-2 at the point (1,0), knowing that the pending point model  is:

y-y_{1}=m(x-x_{1}), we solve y-0 = -2(x-1) ⇒ y=-2x+2

7 0
1 year ago
In the equation below, b and c represent the price per pound, in dollars, of beef and chicken, respectively, x weeks after july
Bumek [7]

Answer:

D

Step-by-step explanation:

Since 1 and c are supposed to be equal, I put 2.35+0.25x=1.75+0.4x and solved that for the x. I got 4. Then, since I want to find the price of the beef, I plugged the 4 in the equation of "b" and got 3.35.

I made many mistakes when solving so I restarted many times which is why it took so long to answer. Whew, I actually found the answer though!

If you want to help, mark me brainliest, I'm only 1 away from getting virtuoso! That would make my day, and hope I made yours.

Bye!

4 0
2 years ago
a motor boat traveled 18 miles down a river in 2 hours but took 4.5 hours to return upstream. Find the rate of the motor boat in
tangare [24]

Answer:

  • rate of the boat in still water = 6.5 miles / hour

  • rate of the current = 2.5 miles / hour.

Explanation:

<u>1) Name the two variables:</u>

  • c: rate of the current
  • b: rate of the boat in still water:

With that, the net rates of the boat down the river and upstrean are:

  • down the river: b + c
  • upstream: b - c

<u>2) Now set the equations for the distance as a function of the times and the rates:</u>

  • distance = rate × time

  • downstream: 18 miles = (b + c) × 2 hours
  • upstream: 18 miles = (b - c) × 4.5 hours

<u>3) Set the system of equations:</u>

  • 18 = 2(b + c) ⇒ 9 = b + c . .  . Equation (1)
  • 18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)

<u>4) Solve the system by </u><u>elimination</u><u>:</u>

  • Add equations (1) and (2): 9 + 4 = 2b
  • Divide both sides by 2: 13/2 = b
  • Simplify: b = 6.5

  • Replace b with 6.5 in equation (2) and solve:

       4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5

<u>5) Results:</u>

  • b = rate of the boat in still water = 6.5 miles / hour

  • c = rate of the current = 2.5 miles / hour.

   

3 0
1 year ago
Read 2 more answers
Casey is deciding which of two landscapers to hire. Each landscaper charges an hourly rate plus a fee for each job. Casey correc
ZanzabumX [31]

which of the two landscapes to hire each landscapes charger an hour rate plus a fee for each job the result of the equator into 20 $20 for 5 hours both landscape charge the same hour rate but not the same fee per job give me your answer

7 0
1 year ago
Read 2 more answers
Apply the distributive property to factor out the greatest common factor. 12 + 20 =
guajiro [1.7K]

We can use prime factorization to find the GCF:

12 = 3^1 \cdot 4^1

20 = 4^1 \cdot 5^1


The greatest value both 12 and 20 share is 4. By factoring this out of the equation, we get:

4(3 + 5) = 4(8) = 32

6 0
1 year ago
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