If N is first and L is last, then we just need to find all of the permutations for M, O, and P
with first letter M: MOP MPO
with first letter O: OPM OMP
with first letter P: PMO POM
Now, place the N in front and the L at the end of each permutation. There are 6 permutations in total:
NMOPL NMPOL
NOPML NOMPL
NPMOL NPOML
Answer:
13 Millilitres.
Step-by-step explanation:
Yoku uses 2ml to cover 
of his skin.
He wants to know how many millilitres of sunscreen he will need to cover 
of his body.
If Yoku covers of his skin will 2ml
He will cover 
of his skin with 
of sunscreen.
Therefore:
To cover of his body, he will use:
he would require 13 Millilitres.
Answer:
a) 0.88
b) 0.35
c) 0.0144
d) 0.2084
e) 0.7916
Step-by-step explanation:
a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88
b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.
c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.
d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084
e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916
The solution would be like
this for this specific problem:
Since the number of
charter schools is eight less than twice the number of alternative schools,
then it’s:
<span>2x - 8 </span><span>
<span>and then
<span>2x - 8 = 36 </span>
<span>2x = 44 </span>
x = 22 </span></span>
So
there are 22 Alternative Schools in
the county. I am hoping that this answer has satisfied your query
and it will be able to help you in your endeavor, and if you would like, feel
free to ask another question.
Answer:
13.20 teaspoon of fertiliser needed for entire garden.
Step-by-step explanation:
Diameter of the garden = 14.50 ft
Radius of the garden = 7.25 ft
Area
[tex]A=\pi r^2[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]\pi=3.14[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]A=3.14 \times 7.25 \times 7.25[/text]
Hence
[tex]A=165.046[/text]
Area is 165.046 Sq Ft
For 25 sq ft of fields the fertiliser needed = 2 tea spoon
For 1 sq ft of fields the fertiliser needed =
[tex]\frac{2}{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed =
[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon
