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LiRa [457]
2 years ago
6

Suppose that lower production costs increases the supply of wheat, such that more wheat is supplied at each price level. After t

he increase in supply, the equilibrium quantity _____.
a) increases
b) decreases
c) stays the same

Mathematics
2 answers:
Alex Ar [27]2 years ago
6 0
Based on the graph, the answer to the question mentioned above is "Equilibrium Quantity Increases" which is the letter "A" in the choices. Suppose that the lower production costs increase the supply of wheat such that more wheat is supplied at each price level. After the increase is supply, the equilibrium quantity increases.
just olya [345]2 years ago
3 0

When the demand and supply curve intersect, that is, where the quantity demanded and quantity supplied are equal, the market is said to be in equilibrium. Thus, the given quantity is equilibrium quantity.

From the graph, we see that when the production cost of wheat is $4, the equilibrium quantity is 600 units.

When the production cost lowers from $4 to $3, the supply of wheat increases, such that the equilibrium quantity increases from 600 units to 800 units.

Thus, after an increase in supply, the equilibrium quantity increases.

So, Option A is the correct answer.

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The function f describes the value of a sculpture after t years. The function g describes the value of a painting by the same ar
Anna11 [10]
H(t) = f(t) - g(t)
= 500(1.2)^t - 380(1.15)^t
Taking out the greatest common factor, which is 20:
= 20[(25)(1.2)^t - (19)(1.15)^t]
This is the third choice.

Note that you cannot subtract the bases of the exponents, for example (1.2^t - 1.15^t) cannot be simplified into something like 0.05^t.
6 0
2 years ago
Read 2 more answers
Isosceles △ABC (AC=BC) is inscribed in the circle k(O). Prove that the tangent to the circle at point C is parallel to AB .
timofeeve [1]

Explanation:

Let M be the midpoint of AB. Then CM is the perpendicular bisector of AB. As such, center O is on CM, and OC is a radius (and CM). The tangent is perpendicular to that radius (and CM), so is parallel to AB, which is also perpendicular to CM.

If you need to go any further, you can show that triangles CMA and CMB are congruent, so (linear) angles CMA and CMB are congruent, hence both 90°.

5 0
2 years ago
A and b are natural numbers. The diameter of cell a is 2.3 , and the diameter of cell b is 2.3 .
Pani-rosa [81]

After clarification we see the respective diameters are

A = 2.3 \times 10^{-a}

B = 2.3 \times 10^{-b}

We're asked about the ratio

A:B =  2.3 \times 10^{-a} :  2.3 \times 10^{-b} = 10^{-a} : 10^{-b} = 10^b : 10^a = 10^{b-a} : 1

Now we can go through the choices.

A. If a = 4 and b = 6, then cell a is 100 times greater than cell b.

A:B=10^{6-4}:1 = 100:1

It would be more proper to say the diameter of cell A is 100 times the diameter of cell B, but yes, this is TRUE.

B. If a = 4 and b = 6, then cell b is 100 times greater than cell a.

FALSE. 10 to the minus 4 is 100 times bigger than 10 to the minus 6, so a is bigger.

C. If a = 4 and b = 6, then cell a is 2 times greater than cell b.

FALSE. We already calculated its 100 times bigger.

D. If a = 4 and b = 6, then cell b is 2 times greater than cell a.

FALSE.


8 0
2 years ago
Read 2 more answers
Mike and Ike are experts at pitching horseshoes. 70% of Mike's tosses are ringers. 67% of Ike's tosses are ringers. Suppose Mike
ahrayia [7]
Mike tosses 70%
Ike tosses 67%
Both tosses 50%

<span>Which of the following is closest to the probability that Ike's proportion is ringers is higher than Mike's for those tosses?
</span>
P(m) = 70/100
P(i) = 67/100
P(b) = 50/100

= P(b) * P(i) 
= 50/100 * 67/100
= 0.335

The correct answer is letter D) 0.3745.
3 0
1 year ago
The area of a square is stored in a double variable named area. write an expression whose value is length of the diagonal of the
lbvjy [14]

First of all, a bit of theory: since the area of a square is given by

A = s^2

where s is the length of the square. So, if we invert this function we have

s = \sqrt{A}.

Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

d = \sqrt{s^2+s^2} = \sqrt{2s^2} = s\sqrt{2}

So, the diagonal is the side length, multiplied by the square root of 2.

With that being said, your function could be something like this:

double diagonalFromArea(double area) {

double side = Math.sqrt(area);

double diagonal = side * Math.sqrt(2);

return diagonal;

}

3 0
1 year ago
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