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Nitella [24]
1 year ago
10

Alberto is making a budget. He owes a cell phone bill of $60 per month for 23 more months, plus the fees for any extra usage suc

h as text messaging or extra minutes. Which of the following is the correct category for this expense?
a.
Essential (flexible) expense
b.
Emergency fund
c.
Essential (fixed) expense
d.
Non-essential expense
Mathematics
2 answers:
Romashka [77]1 year ago
6 0

Answer:

a.  Essential (flexible) expense

Step-by-step explanation:

Most people consider a cell phone an essential expense, since they are used in power outages or emergencies while traveling.

This is a flexible expense, since there are extra fees for extra usage.  

netineya [11]1 year ago
3 0
I'm not sure what your book is saying about the matter but a cell phone is not usually an essential expense. If it is saying it is though, it would be an essential flexible expense. 
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In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded regi
Minchanka [31]
The picture in the attached figure

we know that
Area of circle=pi*r²
area of the shaded region=364*pi cm²
area of the shaded region=area of the outer circle -area of the<span> inside circle

</span>area of the outer circle=pi*[2x]²----> 4*x²*pi cm²
area of the inside circle=pi*6²------> 36*pi cm²
364*pi=4*x²*pi-36*pi------> 364=4*x²-36
4*x²=364+36-----> 4*x²=400
x²=400/4----> x²=100
x=10 cm

the answer is
x=10 cm

4 0
1 year ago
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0
2 years ago
This chart shows what happens when each object is placed on a balance with a 10 kg weight on the other side.
dexar [7]

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Answer:

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Step-by-step explanation:

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Then the relative weights are ...

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8 0
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I think it’s 5.25 cm but you might want to double check.
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Answer:

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