Answer:
let us add 2.4 mL of water in 0.6 ml of coloring solution
total volume of solution = 2.4 + 0.6 = 3 mL
therefore,
0.6 mL of coloring solution now includes = 2.4ml of water
or
1 mL of coloring solution includes = 4mL of water
Hence
measure 3 mL of coloring solution with water that is formed
therefore, this 3 mL will contain 0.6 mL of coloring solution
Step-by-step explanation:
Given:
formula calls for 0.6 mL of a coloring solution
10-mL graduate calibrated from 2 to 10 mL in 1-mL units
Now,
We want to use an aliquot technique to measure 0.6 ml of coloring solution.
Because the calibrated graduate is used to measure 2ml to 10ml with 1ml as unit measure
let us add 2.4 mL of water in 0.6 ml of coloring solution
total volume of solution = 2.4 + 0.6 = 3 mL
therefore,
0.6 mL of coloring solution now includes = 2.4ml of water
or
1 mL of coloring solution includes = 4mL of water
Hence
measure 3 mL of coloring solution with water that is formed
therefore, this 3 mL will contain 0.6 mL of coloring solution
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and 
there are two more solutions:
