A sporting goods manager was selling a ski set for a certain price. The manager offered the markdowns shown on the right, making
2 answers:
Answer:
The original selling price would be $ 515.87 ( approx )
Step-by-step explanation:
Consider the complete question is :
"A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown, making the one-day sale price of the ski set $325. Find the original selling price of the ski set. It was marked down 10% and 30%"
Suppose x be the original selling price ( in dollars ),
After marking down 10%,
New selling price = x - 10% of x = x - 0.1x = 0.9x
Again after marking down 30%,
Final selling price = 0.9x - 30% of 0.9x
= 0.9x - 0.3 × 0.9x
= 0.9x - 0.27x
= 0.63x
According to the question,
0.63x = 325
Therefore, the original selling price would be $ 515.87.
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Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>Step-by-step explanation:
Given the function j(x) = 11.6 and k(x) =
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6 and k(x) =
are inverse functions.
Solution:
As we are given that f(1) = 0 .
It mean that is one of the factor of the given equation.
Remainder theorem can be applied as below:
Hence the factors are (x-1),(x+3) and (x+1).
Hence the correct option is B.