To solve this problem, let us first define what is mean
and median. Mean is the average of all the numbers in the data set while
the median is the number in the middle of the data set in ascending order.
If we create a box plot for the data of Rome and New York,
we can see that there is an outlier in the data for New York. Since New York
has an outlier, so the mean is not a good representation on the central
tendency of the data. The mean is skewed (distorted) by the outlier. So in this
case it is better to use the median.<span>
While the Rome data is nice and symmetrical, it does not seem
to have an outlier, so we can use the mean for this data set.</span>
Therefore the answer is:
<span>The Rome data center is best described by the mean. The
New York data center is best described by the median</span>
<u>The given options are:</u>
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.
(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.
(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.
Answer:
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
Step-by-step explanation:
The area of the shaded sector can be determined using the formula:



Therefore, the formula is:

Therefore, the formula is best explained by Option A.
Hello, there!
5/4 = 1.25
So, we know that the answer is not A or B.
1.25 = 125%
Now, we know that the answer is not D ether.
So, the answer must be C.
I hope I helped!
Let me know if you need anything else!
~ Zoe
Answer:
Yes the sample can be use to make inference
Step-by-step explanation:
The inference is possible if the conditions:
p*n > 10 and q*n > 10
where p and q are the proportion probability of success and q = 1 - p
n is sample size
Then p = 12 / 30 = 0,4 q = 1 - 0,4 q = 0,6
And p*n = 0,4 * 30 = 12 12 > 10
And q*n = 0,6 * 30 = 18 18 > 10
Therefore with that sample the conditions to approximate the binomial distribution to a Normal distribution are met