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torisob [31]
1 year ago
15

Charlie wants to order lunch for his friends. He'll order 5 sandwiches and a $3 kid's meal for his little brother. Charlie has $

28. How much can he spend on each sandwich if they are all the same price? Choose two answers: one for the inequality that models this situation and one for the correct answer.
Mathematics
2 answers:
Dominik [7]1 year ago
8 0
Inequality:
5x - 3 ≤ 28

Answer:
5x - 3 <span>≤ 28
5x </span><span>≤ 31
x </span><span>≤ 31/5 or 6.2 ($6.20)</span>
Harrizon [31]1 year ago
6 0

Answer:

5x + 3 < 28

$5 or less

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Let p denote the proportion of students at a particular university that use the fitness center on campus on a regular basis. For
9966 [12]

Answer:

a) P-value = 0.0968

b) P-value = 0.2207

c) P-value = 0.0239

d) P-value = 0.0040

e) P-value = 0.5636

Step-by-step explanation:

As the hypothesis are defined with a ">" sign, instead of an "≠", the test is right-tailed.

For this type of test, the P-value is defined as:

P-value=P(z>z^*)

being z* the value for each test statistic.

The probability P is calculated from the standard normal distribution.

Then, we can calculate for each case:

(a) 1.30

P-value=P(z>1.30) = 0.0968

(b) 0.77

P-value=P(z>0.77) = 0.2207

(c) 1.98

P-value=P(z>1.98) = 0.0239

(d) 2.65

P-value=P(z>2.65) = 0.0040

(e) −0.16

P-value=P(z>-0.16) = 0.5636

7 0
1 year ago
1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d
TiliK225 [7]

Answer:

1. The amount that was not spent is: 1080 soles

2. The answer is 5.

Step-by-step explanation:

Question 1. There are two situations:

If you spent 5/8 of the money then notice, that u did not spend 3/8.

If you spend 2/5 of the money, then you would have 72 more.

So think, this equation:

3/8x + 72 = 2/5x

2/5 of the money is the value for what you did not spend plus 72, the amount you would have, where x is the answer for the total of money.

72 = 2/5x - 3/8x

72 = 1/40x

x = 2880 soles

As you did not spend 3/8 of 2880, the answer is 1080 soles

Notice that if u spent 2/5 of 2880, you would have 1152 soles, so, the 1080 + 72, as the problem said.

Question 2.

We think letters for this excersise.

N = My born year

2020 (this year) - N = E (my age, now)

So N + 10 = when I get 10 years old

N + 20 = when I get 20 years old

N + 30 = when I get 30 years old

N + 40 = when I get 40 years old

The problem says:

(N+10) + (N+20) - (N+E) = 2020

((N+30)+E) - (N-40) = X  

So if 2020 - N = E, then notice that 2020 - E = N. Let's replace this in the equation form:

((2020-E)+10) + ((2020-E)+20) - ((2020-E)+E) = 2020

No minus in the first two terms, so we can break the ( )

2020-E+10 + 2020-E+20 - ((2020-E)+E) = 2020

We apply the distributive property for the second term

2020-E+10 + 2020-E+20 - 2020+E-E = 2020

We can cancel two E, and the 2020, so the new form will be:

2020 - 2E + 30 = 2020

We can also cancel the 2020, so if we reorder the equation, we have:

-2E = -30

E = 15 That's my age, so my born's year is 2020 - 15 = 2005 (N)

Look:

(2005 + 10) + (2005+20) - (2005+15) = 2020

So now, the last part

((2005+30)+15) - (2005+40) = 5

3 0
1 year ago
In 2013, the national debt was
Reika [66]

Answer:

You can use a calculator for the decimal operations, but practice some by hand because on the quiz and the test you will not have a calculator.

Step-by-step explanation:

7 0
1 year ago
Given the image below, what is the image of C after a dilation with a scale factor of 3
Ne4ueva [31]

Answer: The coordinates of point C after the dilation are (-2, 5)

Step-by-step explanation:

I guess that you want to find where the point C ends after the dilation.

Ok, if we have a point (x, y) and we do a dilation with a scale A around the point (a,b), then the dilated point will be:

(a + A*(x - a), b + A*(y - b))

In this case we have:

(a,b) = (2,1) and A = 3.

And the coordinates of point C, before being dilated, are: (1, 2)

Then the new location of the point C will be:

C' = (1 + 3*(1 - 2), 2 + 3*(2 - 1)) = (1 -3, 2 + 3) = (-2, 5)

6 0
2 years ago
How long will it take before twenty percent of our 1,000-gram sample of uranium-235 has decayed? [See Section 6.6 Example 13] Th
horsena [70]

Answer:

From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.

U-235 half-life is 704,000,000 years. (Wikipedia)

The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]

elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]

elapsed time =7.04 x 10^8 *  [log (1.25) / .30103]

elapsed time =7.04 x 10^8 *  [0.096910 / .30103]

elapsed time = 7.04 x 10^8 *  0.321928047

elapsed time = 226,637,000 years

Step-by-step explanation:

8 0
1 year ago
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