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Semmy [17]
1 year ago
11

How long will it take before twenty percent of our 1,000-gram sample of uranium-235 has decayed? [See Section 6.6 Example 13] Th

e decay equation is A(t)=A_0e^{Kt} , where t is the time for the decay, and K is the characteristic of the material. Suppose T is the time it takes for half of the unstable material in a sample of a radioactive substance to decay, called its half-life. Prove that K= \frac{ln0.5}{T} . What is T for the uranium-235? Show the steps of your reasoning.
Mathematics
1 answer:
horsena [70]1 year ago
8 0

Answer:

From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.

U-235 half-life is 704,000,000 years. (Wikipedia)

The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]

elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]

elapsed time =7.04 x 10^8 *  [log (1.25) / .30103]

elapsed time =7.04 x 10^8 *  [0.096910 / .30103]

elapsed time = 7.04 x 10^8 *  0.321928047

elapsed time = 226,637,000 years

Step-by-step explanation:

You might be interested in
On your birthday you receive a new TV valued at $1199. The value of the TV decreases by 25% each year. What will its value be 4
earnstyle [38]

Answer: 74.93

Step-by-step explanation:   if you heard of the line equals line method this should be able to help you.  

299.75                     25%

---------------=------------------  

$1199                     100%      

so you cross multiply 1199 and 25 and then divide it by 100.   which would be 299.75 that is the price per 1 year then you divide that value by 4 and that will be your answer.  

299.75 divided by 4= 74.93  

hope this helps

4 0
1 year ago
2.14x - 42.9 for x = 22.4 ?<br> A. -18.36<br> B. 5.026<br> C. 47.939<br> D. 90.839
Fynjy0 [20]

Answer:

Step-by-step explanation:

Your answer would be B., because you would multiply

2.14 x  22.4   =

47.939  

then you will subtract that by 42.9

47.939 - 42.9 =  

5.026

7 0
2 years ago
Given: Two concentric circles with Center Point p. How many tangent lines can be drawn that both circles share?
levacccp [35]

Answer: I think that it's not One but It's <u><em>ZERO</em></u> because a tangent line can only touch the circle at one point and if it touches the small circle once it would have to go through the larger one twice.

Edit: I just checked and it's definitely<u><em> ZERO</em></u>

7 0
1 year ago
The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1
AlexFokin [52]

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = 2, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = 2

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = x+1, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = x+1

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

7 0
2 years ago
According to a Wired magazine article, of e-mails that are received are tracked using software that can tell the e-mail sender w
VladimirAG [237]

Answer:

a. 12

b. 7.200 and 2.683

Step-by-step explanation:

The computation is shown below:

Given that

P = 0.40 and n = 30

a)

The expected value of received e-mails is

= n × p

= 30 × 0.4

= 12  

b)

The variance of emails received is

= n × p × (1 - p)

= 30 × 0.4 × 0.6

= 7.200

Now

The standard deviation of emails received is

= sqrt(variance)

= 2.683

We simply applied the above formula

8 0
1 year ago
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