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djverab [1.8K]
1 year ago
12

Which term of the AP. 8 , -4 , -16 , -28 ,......... is -880 ?​

Mathematics
2 answers:
Darina [25.2K]1 year ago
7 0

Answer: 75th term

Step-by-step explanation:

If you look at the first terms, you can see that we're subtracting 12 from the previous term to get the number. Knowing this, we can write an expression for the nth term. The expression would be -12n + 20. Since this specific term has value of -880, we set -880 equal to the value of -12n+20. By setting your equation like this -12n + 20 = -880 and solving, you get n = 75, which means the 75th term has a value of -880.

denis-greek [22]1 year ago
6 0

Answer:

75th term

Step-by-step explanation:

hope it is well understood

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First, we need to solve the differential equation.
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This a separable ODE. We can rewrite it like this:
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Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
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1 year ago
Hamden city’s police department needs to choose whether to build a new addition to the police station or to buy new squad cars.
Romashka [77]

Answer:

The sampling option Hamden city's police department needs to choose is to select a random sample of 10% of all taxpayers.

Since the Hamden city’s police department needs to choose whether to build a new addition to the police station or to buy new squad cars. And it needs money to choose any of these options. The money usually comes from the packets of taxpayers. Therefore, it would be appropriate to take a random sample of 10% of all taxpayers.


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1 year ago
Nancy was laid off and applied for unemployment benefits in July. In her state, the weekly unemployment benefit is 55% of the ​2
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$277.91

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---------------------------- = $13137.50

            2

Dividing this by 26 weeks (equivalent to 6 months), we get $505.29.

Nancy's weekly employment benefit would be 55% of that, or $277.91.

8 0
2 years ago
Amy is biking to school from her father's house and Jeremy is biking to school from his aunt's house. Suppose Amy is moving at a
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No, having the greater rate of change does not mean a function will necessarily reach an output with the smallest input. It also depends on the initial values of the functions. If Jeremy's aunt lives closer to school, Jeremy's rate of change is smaller, but he could still get to school before Amy.

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1 year ago
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A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat
vivado [14]
Analysis to obtain the function that models the polulaiton ob bees:

1) First year 9,000 bees

2) Second year: decrease 5% => 9,000 - 0.05* 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95

3) Every year the population decreases 5% => 9,000 * 0.95)^ (number of years)

4) if you call x the number of years, and f(x) the function that represents the number of bees, then: f(x) = 9,000 (0.95)^ x.

Analysis of the statements:

<span>1) The function f(x) = 9,000(1.05)x represents the situation.

FALSE: WE DETERMINED IT IS f(x) = 9,000 (0.95)^x

2) The function f(x) = 9,000(0.95)x represents the situation.

TRUE: THAT IS WHAT WE OBTAINED AS CONCLUSION OF THE PREVIOUS ANALYSIS.

3) After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.

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f(2) = 9,000 * (0.95)^2 = 9,000 * 0,9025 = 8,122

So, the statement is TRUE

4) After 4 years, the farmer can estimate that there will be about 1,800 bees remaining.

f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330

So, the statement is FALSE

5) The domain values, in the context of the situation, are limited to whole numbers.

FALSE: THE DOMAIN VALUES ARE ALL NON NEGATIVE REAL VALUES. FOR EXAMPLE THE FUNCTION IS WELL DEFINED FOR X = 5 AND HALF

6) The range values, in the context of the situation, are limited to whole numbers.

TRUE: THERE CANNOT BE FRACTIONS OF BEES
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1 year ago
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