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tia_tia [17]
2 years ago
7

Simplify: (-4a + b – 2c) – (3a + 2b –c)

Mathematics
2 answers:
anyanavicka [17]2 years ago
5 0
Because you can’t simplify anymore within the parentheses you add the like terms a, b, and c

irinina [24]2 years ago
5 0

(-4a + b – 2c) – (3a + 2b –c)

-4a+b-2c-3a-2b+c

-7a-b-c

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At a carnival, a particular game requires the player to spin a wheel. When a child plays, the game operator allows them to conti
Bumek [7]

Answer:

(a) and (e) are not valid.

Step-by-step explanation:

a) The number of traials is not fixed. In fact, the random variable counts the total number of trials.

b) This is true, the result of each trial is independent of the others.

c) This is also true. The outcomes are failure and success.

d) This is true as well, all trials are identically distributed.

e) Since (a) is not valid, this cant be true.

4 0
2 years ago
Please solve this equation
Darya [45]

Answer: if you simplify the equation, your answer should be 16

Step-by-step explanation: Simplify  2+22+22+2  to  444.

8÷2×48\div 2\times 48÷2×4

2

Simplify  8÷28\div 28÷2  to  444.

4×44\times 44×4

3

Simplify.

16

4 0
2 years ago
Read 2 more answers
A bowl of flower seeds contains 5 petunia seeds and 15 begonia seeds. Riley calculated the probability that a random selected se
Vlad1618 [11]

Answer:

Riley divided the number of petunia seeds by the number of begonia seeds, getting \frac {5}{15} = \frac {1}{3}. What you actually need to do to calculate the probability of selecting a petunia seed is divide the number of petunia seeds by the <em>total</em> number of seeds. 5 petunia seeds and 15 begonia seeds makes 20 total seeds, so you divide 5 petunia seeds by 20 total seeds to get \frac {5}{20} = \frac {1}{4}.

7 0
2 years ago
A box of buttons contains the same number of each type of button. It contains 220g of buttons
ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

6 0
2 years ago
The point R is halfway between the integers on the number line below and represents the number ____. (Use the hyphen for negativ
wariber [46]

Answer: - 2.5

Step-by-step explanation:

Using the attached number line has reference, the distance between each integer on the number line attached is 1, and the numbers are ordered in ascending order from - 10 to + 10. The point R exists in between the point marked - 2 and - 3 respectively. This shows that that point R is a number between the two integers, a number greater than - 3 but less than - 2.

From the picture attached the blue dot sits directly at the midpoint between - 3 and - 2. Hence the position can be a obtained by averaging the two integers.

(-3 + - 2) / 2 = - 5/2 = - 2.5

3 0
2 years ago
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