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tatuchka [14]
2 years ago
5

For what values of x is x2-36=5x true?

Mathematics
2 answers:
Inessa05 [86]2 years ago
6 0

Answer:

X = -12

Step-by-step explanation:

x2-36=5x

take away 2x from both sides

-36=3x

divide both sides by 3

X = -12

katrin2010 [14]2 years ago
3 0

Answer:

x=-12

Step-by-step explanation:

x2-36=5x

add 36 to both sides

x2=5x+36

subtract 5x from both sides

x(-3)=36

divide both sides by -3

x=-12

substitute to prove right

(-12)2-36=5(-12)

-24-36=-60

-60=-60

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A ball is drawn at random from a container that holds 8 yellow balls numbered 1 to 8, 6 orange balls numbered 1 to 6, and 10 gra
Margarita [4]
A)

total of balls = 8+6+10= 24 balls 

3/24= .125 and it is 12.5 % that one of the orange balls is 5 because it is an odd number.

B) 

4/24 =.167 0r 16.7% that of the gray balls is numbered 8.


6 0
2 years ago
Below are boxplots that summarize the weights (in pounds) of large samples from two breeds of dog: the Anatolian Shepherd and th
koban [17]

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

5 0
2 years ago
Piper works at a camera store. He is pain an hourly rate plus 16% commission on everything he sells. One week, he was paid $365
MAXImum [283]
I believe it's a) $6.25

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5 0
2 years ago
Read 2 more answers
1. HELP Use front-end estimation to estimate the sum 8.86 + 9.43 + 5.75
marta [7]

Answer:

1. Option D.

2. Option A.

Step-by-step explanation:

1. You need to follow these steps in order to estimate the sum of 8.86 + 9.43 + 5.75:

Step 1: Add the digits in the ones places of the whole numbers (these are: 8, 9 and 5).

Step 2: Round the decimals to the nearest whole number:

0.86\approx 1\\\\0.43\approx0\\\\0.75\approx1

 Step 3: Add them together:

8+9+5+1+0+1=8+9+5+2=24

2. The procedure to estimate  the difference of 83.92-47.23 is:

83.92-\\47.23\\........\\40.00\\\ -4.00\\\ \ + 0.70\\-0.01\\...........\\+36.00\\+0\ 0.69\\..............\\36.69

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36.69\approx 37

5 0
2 years ago
Helps pls HELPPPPPPP
Brrunno [24]

Answer: Third option.

Step-by-step explanation:

Let be "x" the approximate actual width  (in feet) of the car.

Based on the information provided in the exercise, you know that the scale of the model car is this one:

1:32

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\frac{1}{32}

Therefore, if you know that the width of the model car is 2.3 inches, you can set up the following proportion:

\frac{1}{32}=\frac{2.3}{x}

Finally, you must solve for "x" in order to find its value.

So you get the following result:

(x)(\frac{1}{32})=2.3\\\\x=(2.3)(32)\\\\x=73.6

8 0
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