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Vadim26 [7]
2 years ago
11

Which graph represents the function f (x) = StartFraction 1 Over x + 3 EndFraction minus 2? On a coordinate plane, a hyperbola i

s shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 3, and the horizontal asymptote is at y = negative 2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens down and to the left in quadrants 2 and 3. A vertical asymptote is at x = 3, and the horizontal asymptote is at y = negative 2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens down and to the left in quadrants 2 and 3. A vertical asymptote is at x = negative 3, and the horizontal asymptote is at y = 2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1 , and the other curve opens down and to the left in quadrants 2, 1, and 4. A vertical asymptote is at x = 3, and the horizontal asymptote is at y = 2.
Mathematics
2 answers:
Zinaida [17]2 years ago
6 0

Answer:

D on edge 2020

Step-by-step explanation:

Ede4ka [16]2 years ago
5 0

Answer:

its A

Step-by-step explanation:

i just did it swag

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Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
quester [9]

Answer:

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

Step-by-step explanation:

I just took the quiz, I hope this helps :).

7 0
1 year ago
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The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the
navik [9.2K]

Answer:

a) 0.019

b) 0.563

c) x = 1.966 hours

Step-by-step explanation:

E(X) = 1

Exponential random variable's probability function is given as

P(X=x) = λ e^(-λ.x)

The cumulative distribution function is given as

P(X ≤ x) = 1 - e^(-λ.x)

a) The time between the arrivals of small aircraft at a county airport that is exponentially distributed.

But the number of planes that land every hour will be obtained using the Poisson distribution formula.

It is the best for discrete systems.

Poisson distribution formula is given as

P(X = x) = (e^-λ)(λˣ)/x!

λ = 1 aircraft per hour.

The probability that more than three aircraft arrive within an hour = P(X > 3)

P(X > 3) = 1 - P(X ≤ 3) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)]

P(X > 3) = 1 - 0.98101 = 0.01899 = 0.019 to 3 d.p

b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals

Probability of one 1-hour interval not containing more than 3 arrivals = 1 - P(X > 3)

= 1 - 0.01899 = 0.98101

Probability that thirty 1-hour intervals will not contain more than 3 arrivals = (0.98101)³⁰ = 0.5626 = 0.563 to 3 d.p

c) Determine the length of an interval of time (In hours) such that the probability that no arrivals occur during the interval is 0.14

We can now use the cumulative distribution function for exponential random variable for this

P(X ≤ x) = 1 - e^(-λ.x)

P(X > x) = 1 - P(X ≤ x)

P(X > x) = e^(-λ.x)

λ = 1, x = ?,

0.14 = e⁻ˣ

e⁻ˣ = 0.14

In e⁻ˣ = In 0.14 = -1.966

-x = -1.966

x = 1.966 hours

Hope this Helps!!!

4 0
2 years ago
A movie theater manager wants to determine whether popcorn sales have increased since the theater switched from using "butter-fl
labwork [276]

Answer:

The function that would correctly calculate the 90% range of likely sample means is given by:

B. 4,200±CONFIDENCE.T(0.10,140,12)

Step-by-step explanation:

In Microsoft Excel, the syntax

CONFIDENCE.T(alpha,standard-dev,size)  returns the confidence  interval for the population mean, using the students T-distribution.Alpha=1-90\%=10\%=0.10

The standard deviation is given as $140 and the sample size is 12.

In constructing the confidence  interval we use:

\bar X\pm CONFIDENCE.T(alpha,standard-dev,size)  

Let us substitute the values to get:

4,200\pm CONFIDENCE.T(0.10,140,12)

We use the T distribution because \sigma is unknown

8 0
2 years ago
The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?
Aleks04 [339]

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

  • The selling price of a box of crackers is $1.75
  • You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = \frac{New-Old}{old} × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = \frac{2.54-1.75}{1.75} × 100%

∴ The markup percentage = \frac{0.79}{1.75} × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

#LearnwithBrainly

8 0
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Calculate the monthly payment for a 5-year car loan of $23,570 at 10.43% interest, compounded monthly. A. $247.44 b. $337.56 c.
earnstyle [38]

The answer is D on E2020!! I just took the test, you can trust this answer

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2 years ago
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